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user100 [1]
2 years ago
5

FIRST PERSON WILL BE MARKED BRAINLIEST! 50 POINTS!

Physics
1 answer:
Tomtit [17]2 years ago
4 0

Answer:

D- Strong and gravitational

Explanation:

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Which statement correctly describes the relationship between frequency and wavelength?
Len [333]
The relationship between the frequency and wavelength of a wave is given by the equation:

v=λf, where v is the velocity of the wave, λ is the wavelength and f is the frequency. 

If we divide the equation by f we get:

λ=v/f

From here we see that the wavelength and frequency are inversely proportional. So as the frequency increases the wavelength decreases. 

So the second statement is true: As the frequency of a wave increases, the shorter the wavelength is.  
3 0
3 years ago
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Explain the difference between what Isaac Newton and Louis de Broglie would have to say about the momentum of a particle that is
pishuonlain [190]

Answer:

Explained

Explanation:

Newton would resort to the classical mechanics and say that the momentum of the particle that is moving with a constant velocity will be given by: momentum = mass x velocity

this approach will highlight the particle nature and will not be relativistic.

De-Broglie will say that the momentum of the particle is related to its associated matter wave and the relation between them is given by:

p = \frac{h}{\lambda}

where \lambda = wavelength of the matter wave associated to the particle, h = planck's constant

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6 0
3 years ago
Say the tortoise and the hare are racing. If the tortoise moves straight
Rina8888 [55]

Explanation:

It's displacement would be negative

displacement is a vector quantity.

'Backwards', we can assume, would be negative.

and forwards, positive. So going backwards would mean a negative displacement.

5 0
3 years ago
Females are the only gender capable of suffering from an eating disorder.<br> A. true<br> B. false
AnnZ [28]
ANSWER
That’s false!!
8 0
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What is the slope if an object comes to a stop then remains at rest?
KIM [24]

It woul be 0 because it is not moving. It is staying at a constant rate.

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