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3 years ago

Whats the sum of all even numbers between 2 and 1000

Mathematics

2 answers:

GrogVix [38]3 years ago

6 0

Answer is: 250500

x=0y=0
while(x<=1000): y += x x += 2
print(y)

dedylja [7]3 years ago

4 0

His allows you to set up a summation of the form:

Summation from i = 1 to 500 of i.

The general solution to the summation of i from 1 to n is n(n+1)/2. In this case, n = 500.

500(501)/2 = 125250

Recall that you divided the sum by 2 to simplify its computation. Now multiply your result by 2 for your final answer:

125250 * 2 = 250500

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Sonja [21]

The sum of the two rational equations is equal to (3 · n² + 5 · n - 10) / (3 · n³ - 6 · n²).

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2 years ago

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mario62 [17]

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3 years ago

Company B: starting salary-28,000 Yearly salary increase-2,400

Naya [18.7K]

Answer:

Sharla, 4400

Step-by-step explanation:

Paul's Salary:

Paul started at company B. Starting salary of company B is $ 28,000 with a yearly increase of $ 2,400. Paul's Salary in first year will be 28,000. In second year his salary will be 28000 + 2400, in 3rd year his salary will be: 28000 + 2(2400) and so on.

Since, the increase in Paul's salary every year is $ 2400, the increase in his salary after 10 years or in 10th year would be = 2400 x 9 = $ 21,600

So, his total salary in 10th year would be = 28000 + 21600 = $ 49,600

Sharla's Salary:

Sharla started at company C. Starting salary of company C is $ 36,000 with a yearly increase of $ 2,000.

Since, the increase in Sharla's salary every year is $ 2000, the increase in her salary after 10 years or in 10th year would be = 2000 x 9 = $ 18,000

So, her total salary in 10th year would be = 36000 + 18000 = $ 54,000

Conclusion:

Sharla earned more in 10th year an amount equal to $ 4400. So the answer is:

In the last year, Sharla earned $4,400 more.

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3 years ago

2x-3y=-2 4x+y=24 What is the first steps to solve the system?

olganol [36]

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7 0

3 years ago

Enrollment at ELAC decreased by 5%, or 600 people, the year. How many people were enrolled last year?

babymother [125]

Answer:

12,000.

Step-by-step explanation:

Let x be the number of people that were enrolled last year.

We have been given that enrollment at ELAC decreased by 5%, or 600 people, the year. We are asked to find the number of people that were enrolled last year.

We can set as equation such that 5% of x equals 600.

$\frac{5}{100}\cdot x=600$

$0.05x=600$

$\frac{0.05x}{0.05}=\frac{600}{0.05}$

$x=12,000$

Therefore, 12,000 people were enrolled last year.

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4 years ago