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3 years ago

Whats the sum of all even numbers between 2 and 1000

Mathematics

2 answers:

GrogVix [38]3 years ago

6 0

Answer is: 250500

x=0y=0
while(x<=1000): y += x x += 2
print(y)

dedylja [7]3 years ago

4 0

His allows you to set up a summation of the form:

Summation from i = 1 to 500 of i.

The general solution to the summation of i from 1 to n is n(n+1)/2. In this case, n = 500.

500(501)/2 = 125250

Recall that you divided the sum by 2 to simplify its computation. Now multiply your result by 2 for your final answer:

125250 * 2 = 250500

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In a class 30 students,20 students like to play cricket and 15 like to play valleyball. Also each student like to play at least

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Answer:

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3 years ago

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If f(3)=5 and f(4)=8 what does f(5)= and f(6)=

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3 years ago

A manufacturing company produces 3 different products A, B, and C. Three types of components, i.e., X, Y, and Z, are used in the

Murljashka [212]

Answer:

Step-by-step explanation:

Using the Excel Formula:

Decision Variable Constraint Constraint

A 65 65 100

B 80 80 80

C 90 90 90

14100 300 300

= (150 *B3)+(80*B4) +(65*B5)-(100-B3+80-B4+90-B5)*90

Now, we have:

Suppose A, B, C represent the number of units for production A, B, C which is being manufactured

A B C Unit price

Need of X 2 1 1 $20

Need of Y 2 3 2 $30

Need of Z 2 2 3 $25

Price of

manufac - $200 $240 $220

turing

Now, for manufacturing one unit of A, we require 2 units of X, 2 units of Y, 2 units of Z are required.

Thus, the cost or unit of manufacturing of A is:

$20 (2) + $30(2) + $25(2)

$(40 + 60 + 50)

= $150

Also, the market price of A = $200

So, profit = $200 - $150 = $50/ unit of A

Again;

For manufacturing one unit of B, we require 1 unit of X, 3 units of Y, and 2 units of Z are needed and they are purchased at $20, $30, and 425 each.

So, total cost of manufacturing a unit of B is:

= $20(1) + $30(3) + $25(2)

= $(20 + 90+50)

= $160

And the market price of B = $240

Thus, profit = $240- $160

profit = $80

For manufacturing one unit of C, we have to use 1 unit of X, 2 unit of Y, 3 units of Z are required:

SO, the total cost of manufacturing a unit of C is:

= $20 (1) + $30(2) + $25(3)

= $20 + $60 + $25

= $155

This, the profit = $220 - $155 = $65

However; In manufacturing A units of product A, B unit of product B & C units of product C.

Profit --> 50A + 80B + 65C

This should be provided there is no penalty for under supply of there is under supply penalty for A, B, C is $40

The current demand is:

100 - A

80 - B

90 - C respectively

So, the total penalty

${(100 - A) + (80 - B) +(90 - C) } + \$40$

This should be subtracted from profit.

So, we have to maximize the profit

$Z = 50A + 80B + 65C = {(100 -A) + (80 - B) + (90 - C)};$

Subject to constraints;

we have the total units of X purchased can only be less than or equal to 300 due to supplies capacity

Then;

$2A + B +C \le 300$ due to 2A, B, C units of X are used in manufacturing A, B, C units of products A, B, C respectively.

Next; demand for A, B, C will not exceed 100, 80, 90 units.

Hence;

$A \le 100$

$B \le 80$

$C \le 90$

and $A, B, C \ge 0$ because they are positive quantities

The objective is:

$\mathbf{Z = 50A + 80B + 65 C - (100 - A + 80 - B + 90 - C) * 40}$

A, B, C $\to$ Decision Varaibles;

Constraint are:

$A \le 100 \\ \\ B \le 100 \\ \\ C \le 90 \\ \\2A + B + C \le 300 \\ \\ A,B,C \ge 0$

6 0

3 years ago

Which statements about the values of 4.099 and 40.99 are true? Select all that apply. 4.099 is 110 of 40.99. 4.099 is 1100 of 40

liraira [26]

Answer:

40.99 is 10 times more than 4.099

Step-by-step explanation:

Given the values :

4.099 and 40.99

4.099 is 110 of 40.99 : 110 * 40.99 = 4508.9 (false)

4.099 is 1100 of 40.99 : 1100 * 40.99 = 45089 (false)

40.99 is 10 times more than 4.099 : (10 * 4.099) = 40.99 (true)

40.99 is 100 times more than 4.099 : (100 * 4.099) = 409.9 ( false)

4.099 is 10 times more than 40.99 : (10 * 40.99) = 409.9 (false)

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3 years ago

20% of the total candy in a basket is Reese's chocolate. There are 8 Reese's in the basket. What is the total number of pieces o

Likurg_2 [28]

Answer:

I believe it is 40. I'm not 100% sure though

Step-by-step explanation:

If 20% of the candy is reese's and there are 8 reese's in the basket, to find the answer you must multiply 8 by 5. You multiply 8 by 5 because to get 100% you have to multiply 20% by 5 to get 100%.

6 0

3 years ago