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Stels [109]
3 years ago
6

Are all these a chemical change Burn Dissolve Rust Explode

Physics
1 answer:
zloy xaker [14]3 years ago
6 0
Rust is not because it does not occur through a chemical process
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Someone pls help me will give brainlist
Crazy boy [7]

Answer:

The volume is 5.6 L

The mass is 100.2g

Explanation:

Quantitative observations are more based on numbers and values

6 0
3 years ago
Could a mixture be made only element and no compounds
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Take the tiny bit of carbon dioxide and the tiny bit of water vapor out of the air,
and the rest of what you're breathing right now is a mixture of elements.

4 0
3 years ago
What is the SI unit for momentum?
serg [7]
It’s a vector quantity, which means it possesses both magnitude and direction. So the SI unit would be B)kg•m/s
4 0
3 years ago
Read 2 more answers
In a closed system, the loss of momentum of one object ________ the gain in momentum of another object.
Virty [35]

In a closed system, the loss of momentum of one object is same as________ the gain in momentum of another object

according to law of conservation of momentum, total momentum before and after collision in a closed system in absence of any net external force, remains conserved . that is

total momentum before collision = total momentum after collision

P₁ + P₂ = P'₁ + P'₂

where P₁ and P₂ are momentum before collision for object 1 and object 2 respectively.

P'₁ - P₁  = - (P'₂ -  P₂)

so clearly gain in momentum of one object is same as the loss of momentum of other object

8 0
3 years ago
A boy whirls a stone in a horizontal circle of radius 1.4 m and at height 1.5 m above ground level. The string breaks, and the s
balandron [24]

Answer:233.23 m/s^2

Explanation:

Given

radius of circle=1.4 m

Height of stone above ground=1.5 m

Horizontal distance(R)=10 m

It is given at the time of break stone flies horizontally thus stone to cover a height of 1.5 m in time t before reaching ground

1.5=0+\frac{gt^2}{2}

t=0.55 s

Initial horizontal velocity at the time of break is given by u

R=u\times t

10=u\times 0.55

u=18.07 m/s

Therefore magnitude of centripetal acceleration is given by

a_c=\frac{u^2}{r}=\frac{18.07^2}{1.4}=233.23 m/s^2

6 0
3 years ago
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