Answer:
amount of aspirin dissolved = 0.0031 g
so we can say that this is not affect % yield as amount of aspirin lost is very less
Explanation:
given data
mass of aspirin = 1 g
volume of water = 450 mL
solubility of aspirin temperature = 10° C
volume of water added = 1.4 mL
to find out
how much amount aspirin would be lost
solution
we know the solubility of aspirin is
solubility of aspirin = ![\frac{mass\ of\ aspirin}{volume\ of\ water}](https://tex.z-dn.net/?f=%5Cfrac%7Bmass%5C%20of%5C%20aspirin%7D%7Bvolume%5C%20of%5C%20water%7D)
solubility of aspirin =
solubility of aspirin = 2.2 ×
g/mL
so
we can say
amount of aspirin dissolved = solubility of aspirin × volume of water added
put here value
amount of aspirin dissolved = 2.2 ×
× 1.4
amount of aspirin dissolved = 3.1 ×
g
amount of aspirin dissolved = 0.0031 g
so we can say that this is not affect % yield as amount of aspirin lost is very less
Answer:
D
Explanation:
Anyone could be leaning forward toward the speaker but be distracted and I believe if you're paying attention to the speaker, you would ask questions to make sure you're understanding what they are speaking
Answer: A 100-lb child stands on a scale while riding in an elevator. Then, the scale reading approaches to 100lb, while the elevator slows to stop at the lowest floor
Explanation: To find the correct answer, we need to know more about the apparent weight of a body in a lift.
<h3>What is the apparent weight of a body in a lift?</h3>
- Consider a body of mass m kept on a weighing machine in a lift.
- The readings on the machine is the force exerted by the body on the machine(action), which is equal to the force exerted by the machine on the body(reaction).
- The reaction we get as the weight recorded by the machine, and it is called the apparent weight.
<h3>How to solve the question?</h3>
- Here we have given with the actual weight of the body as 100lbs.
- This 100lb child is standing on the scale or the weighing machine, when it is riding .
- During this condition, the acceleration of the lift is towards downward, and thus, a force of ma .
- There is also<em> mg </em>downwards and a normal reaction in the upward direction.
- when we equate both the upward force and downward force, we get,
i.e. during riding the scale reads a weight less than that of actual weight.
- When the lift goes slow and stops the lowest floor, then the acceleration will be approaches to zero.
Thus, from the above explanation, it is clear that ,when the elevator moves to the lowest floor slowly and stops, then the apparent weight will become the actual weight.
Learn more about the apparent weight of the body in a lift here:
brainly.com/question/28045397
#SPJ4
Answer:
it is a force
Explanation:
a force is a push or a pull