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blsea [12.9K]
3 years ago
11

SNC2L Reflection Activities

Chemistry
1 answer:
slega [8]3 years ago
4 0

The reflection from plane mirror is shown in the diagram.

<h3><u>Explanation</u>:</h3>

The mirror is a plane surface which can reflect light. The diagram attached shows the schematic representation of reflection that occurs in a plane mirror.

The laws of reflection states that the incident ray, reflected ray and the normal at the point of incidence lies at the same plane. Here we can also see that all are lying on a same plane.

The second law states that angle of incidence is equal to angle of reflection. Here we can also see that the i =r. It is applicable here too.

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cohesion

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Select all of the following which are characteristics of metals.
shtirl [24]

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8 0
2 years ago
Activity A moles need hlp
damaskus [11]
I would always start by balancing your carbons, and then balancing the rest from there.

1. C2H5OH + O2 —> CO2 + H2O - You have two carbons on the left and one on the right. Multiply CO2 by 2.
C2H5OH + O2 —> 2CO2 + H2O

Now balance hydrogen. You have 6 on the left and 2 on the right. Multiply H2O by 3.
C2H5OH + O2 —> 2CO2 + 3H2O

Now balance oxygen. You have 3 on the left and 7 on the right. You need 4 more on the left. Don’t multiply the C2H5OH by anything because that will change the numbers of everything else too. Multiply O2 by 3 instead.
C2H5OH + 3O2 —> 2CO2 + 3H2O

Check that all atoms are now balanced, and you’re good.

2. Same process as before.

First carbons - C3H8 + O2 —> 3CO2 + H2O
Then hydrogens - C3H8 + O2 —> 3CO2 + 4H2O
Then oxygens - C3H8 + 5O2 —> 3CO2 + 4H2O

3. Same again.

Carbons) C6H12O6 + O2 —> 6CO2 + H2O
Hydrogens) C6H12O6 + O2 —> 6CO2 + 6H2O
Oxygens) C6H12O6 + 6O2 —> 6CO2 + 6H2O

4. The general reaction for a combustion reaction is a hydrocarbon reacting with oxygen to produce carbon dioxide and water.
7 0
2 years ago
What volume would 0.735 moles of O2 gas occupy at STP
tatiyna

Answer:

16.5 dm³

Explanation:

Data Given:

no. moles of O₂ =  0.735 moles

volume of O₂ = ?

Solution:

Now

we have to find volume of O₂ gas

Formula used for this purpose

                   No. of moles = Volume / molar volume

where

molar volume at STP for Oxygen (O₂) = 22.4 dm³/mol

              No. of moles O₂ = Volume of O₂ / 22.4 dm³/mol . . . . . .(1)

Put values in equation 1

                0.735 = Volume of O₂ / 22.4 dm³/ mol

rearrange above equation

              Volume of O₂ = 0.735 x 22.4 dm³/ mol

              Volume of O₂ = 16.5 dm³

So,

the volume of O₂ at STP is 16.5 dm³

6 0
3 years ago
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