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blsea [12.9K]
4 years ago
11

SNC2L Reflection Activities

Chemistry
1 answer:
slega [8]4 years ago
4 0

The reflection from plane mirror is shown in the diagram.

<h3><u>Explanation</u>:</h3>

The mirror is a plane surface which can reflect light. The diagram attached shows the schematic representation of reflection that occurs in a plane mirror.

The laws of reflection states that the incident ray, reflected ray and the normal at the point of incidence lies at the same plane. Here we can also see that all are lying on a same plane.

The second law states that angle of incidence is equal to angle of reflection. Here we can also see that the i =r. It is applicable here too.

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The right answer is centuries

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What are the energy transformations in a fossil fuels power plant?
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Solve this problems using the equation: C = λ x ν........ A microwave oven emits radiation at a wavelength of 5.00 x 10e-5 m. Wh
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c = λ x ν

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Ammonium nitrate, a common fertilizer, is used as an explosive in fireworks and by terrorists. It was the material used in the t
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Explanation:

The given balanced reaction is as follows.

           2NH_{4}NO_{3} \rightarrow 2N_{2} + O_{2} + 4H_{2}O

It is given that mass of ammonium nitrate is 86.0 kg.

As 1 kg = 1000 g. So, 86.0 kg = 86000 g.

Hence, moles of NH_{4}NO_{3} present will be as follows.

      Moles of NH_{4}NO_{3} = \frac{mass given}{\text{molar mass of NH_{4}NO_{3}}}

                                  = \frac{86000 g}{80.043 g/mol}

                                  = 1074.42 mol

Therefore, moles of N_{2}, O_{2} and H_{2}O produced by 1074.42 mole of NH_{4}NO_{3} will be as follows.

  Moles of O_{2} = \frac{1}{2} \times 1074.42 mol

                                = 537.21 mol

Moles of N_{2} = \frac{2}{2} \times 1074.42 mol

                                = 1074.42 mol

Moles of H_{2}O = \frac{4}{2} \times 1074.42 mol

                                = 2148.84 mol

Therefore, total number of moles will be as follows.

          537.21 mol + 1074.42 mol + 2148.84 mol

        = 3760.47 mol

According to ideal gas equation, PV = nRT. Hence, calculate the volume as follows.

                       PV = nRT

                     1 atm \times V = 3760.47 mol \times 0.0821 L atm/mol K \times 580 K[/tex]         (as 307^{o}C = 307 + 273 = 580 K)

                           V = 179066.06 L

Thus, we can conclude that total volume of the gas is 179066.06 L.

3 0
3 years ago
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