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Andrews [41]
3 years ago
14

What momentum of a 50kilogram ice skater gliding across the ice at a speed of 5m/s?

Physics
2 answers:
kirill [66]3 years ago
7 0

Answer:

Momentum (P) = Mass (kg) * Velocity (m/s)

P = M * V

P = 50 * 5

P = 250

So momentum is 250 kgm/s

Explanation:

Ivenika [448]3 years ago
5 0
Momentum (P) = Mass (kg) * Velocity (m/s)

P = M * V
P = 50 * 5
P = 250

So momentum is 250 kgm/s

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A hiker walks 11 km due north from camp and then turns and walks 11 km due east. What is the magnitude of the displacement (on a
sattari [20]

Answer:

16 km

Explanation:

Drawing a right triangle to model the problem helps. I started by drawing the lines of the triangle to model the hiker's journey- a vertical straight line for 11 km north and then a horizontal line connected to the top of it for 11 km east; I then drew the hypothenuse to connect the two lines.

The hypothenuse is what we have to solve for, so we will use the Pythagorean Theorem, a^2 + b^2 = c^2. Since both distances are 11 km both a and b in the equation are 11.

11^2 + 11^2 = c^2

121 + 121 = c^2

242 = c^2

c = 15.56

Rounding the answer makes it 16 km for the hiker's magnitude of displacement.

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Fermentation is a _________ process.
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4 0
3 years ago
A spring with k = 53 N/m hangs vertically next to a ruler. The end of the spring is next to the 18 cm mark on the ruler. If a 2.
Anarel [89]

Answer:

1.07 m

Explanation:

x = Compression of the spring

k = Spring constant = 53 N/m

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P = Kinetic energy

K = Kinetic energy

At the lowest point of the mass the energy conservation is as follows

P_{ig}+P_{is}+K_i=P_{fg}+P_{fs}+K_f\\\Rightarrow mgx+0+0=mgx+\frac{1}{2}kx^2\\\Rightarrow x=\frac{2mg}{k}\\\Rightarrow x=\frac{2\times 2.4\times 9.81}{53}\\\Rightarrow x=0.89\ m

At its lowest position the mark on the ruler will be

x_f=0.18+0.89\\\Rightarrow x_f=1.07\ m

The spring line will end up at 1.07 m

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Answer:

It takes more force to accelerate a dump truck

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