Which term refuses to the structure that forms the surface of a cell, separating it's contents from the outside world

A teacher gives a test to two algebra classes. The first class has 18 students, and the second has 24 students. If the average f

Morgarella [4.7K]

Answer:

The <em>C)</em> statement is true.

Explanation:

Let's call <em> $x_1$ </em> the average for the first class and <em> $x_2$ </em>the average for the second class. The overall average <em>x</em> is then:

$x=\frac{x_1*18+x_2*24}{18+24}\\x=\frac{84*18+x_2*24}{42}\\x=\frac{1512+x_2*24}{42}$

Since the average is given by <em> $Average=\frac{Sum of all values}{Amount of values}$ </em>. We can now calculate <em>x</em> assuming the maximun and minimun values of <em> $x_2$ </em>, 2400 (which is 100 times 24) and 0 respectivly. That gives:

$x=\frac{1512+2400}{42}\\x=93$

for it's maximun value and

$x=\frac{1512+0}{42}\\x=36$

for it's minimun value. So we get that <em>x</em> is between 36% and 93%.

5 0

3 years ago

A thin-walled sphere rolls along the floor. What is the ratio of its translational kinetic energy to its rotational kinetic ener

ICE Princess25 [194]

Explanation:

The kinetic energy of translation

$E_1=\frac{1}{2}mv^2$

m= mass v= linear velocity

The kinetic energy of rotation

$E_2=\frac{1}{2}I\omega^2$

I= MOI of the thin walled sphere =kmR^2

where ω= v/R= angular velocity

$E_2=\frac{1}{2}kmR^2\frac{v}{R}^2$

Then

$\frac{E_1}{E_2} = \frac{0.5mv^2}{0.5kmR^2\frac{v}{R}^2 }$

=1/k

solid sphere: k=0.4; E1/E2 =1/0.4 = 2.5;

hollow sphere: k=2/3; E1/E2 = 1.5

3 0

3 years ago

There is some gas in a container at pressure 136 atm. When 142 dm3 gas is released at pressure of 1 atm,then the pressure of the

mamaluj [8]

Answer:

228.7 $dm^{3}$

Explanation:

According to Boyle's law

P1V1 = P2V2

where P1& P2 are initial and final pressure

and V1& V2 and initial and final volumes respectively.

Given:

P1 = 136atm, P2 = 131.6atm

V1 = 142 $dm^{3}$ ; V2 = ?

V2 = $\frac{P1V1}{P2}$ = $\frac{136*142}{131.6}$

= 146.7 $dm^{3}$

Total volume, V = V1 + V2

=146.7 + 142

8 0

3 years ago

If a substance has a mass of 12.50 g and takes up 3.4 mL of space, what is the density?

miskamm [114]

Answer:

The answer is

Explanation:

The density of a substance can be found by using the formula

<h3> $density = \frac{mass}{volume}$ </h3>

From the question

mass of substance = 12.50 g

volume = 3.4 mL

The density of the substance is

$density = \frac{12.50}{3.4} \\ = 3.676470588...$

We have the final answer as

Hope this helps you

7 0

3 years ago

The last intermediate in citric acid cycle is:_________

GenaCL600 [577]

The last intermediate in citric acid cycle is Oxaloacetic acid.

<h3>What is Citric Acid Cycle?</h3>

Organic molecule HOC(CO2H)(CH2CO2H)2 is the chemical formula for citric acid. It is a weak organic acid that is colorless. Citrus fruits naturally contain it. It is a biochemical intermediary in the citric acid cycle, which is a component of all aerobic organisms' metabolism.

Every year, more than two million tons of citric acid are produced. It is frequently used as a flavoring, an acidifier, and a chelating agent.

Citrates, which include salts, esters, and the polyatomic anion present in solution, are derivatives of citric acid. Trisodium citrate is an example of the former; triethyl citrate is an example of an ester.

Learn more about citric acid with the help of the given link:

brainly.com/question/15582668

#SPJ4

7 0

1 year ago