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Answer:
77.14 atm of pressure should be of an acetylene in the tank.
Explanation:
According to reaction, 2 moles of acetylene reacts with 5 moles of oxygen.
Moles of oxygen=
Moles of acetylene =
Volume of large tank with oxygen gas,
Pressure of the oxygen gas inside the tank =
..[1]
Volume of small tank with acetylene gas ,
Pressure of the acetylene gas inside the tank =
..[2]
Considering both the gases having same temperature T, [1]=[2]
77.14 atm of pressure should be of an acetylene in the tank.
Answer:
d. a) no change in the equilibrium and
b) equilibrium shifts towards products.
Explanation:
Hello.
In this case, for the reaction:
Which is endothermic due to the positive enthalpy of reaction. In such a way, based on the Le Chatelier's principle which states that increasing the temperature of an endothermic chemical reaction shifts the equilibrium towards products as heat is understood as a reactant, we can see, this is the case.
Moreover, since the change in the number of gaseous moles in the chemical reaction (coefficients balancing the reaction) is 0 (1+1-1-1), we can see that increasing the total pressure does not have any effect over equilibrium.
Therefore answer is d. a) no change in the equilibrium and b) equilibrium shifts towards products.
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