Give the number of lone pairs around the central atom and the geometry of the ion IBr2.
1 answer:
Answer:
Option E!
Explanation:
If we were to draw the lewis dot structure for IBr2 -, we would first count the total number of valence electrons ( " available electrons " ). Iodine has 7 valence electrons, and so does Bromine, but as Bromine exists in 2, the total number of valence electrons would be demonstrated below;
Don't forget the negative on the Bromine!
Now go through the procedure below;
1 ) Place Iodine in the middle and draw single bonds to each of the bromine.
2 ) Add three lone pairs on each of the Bromine's
3 ) Now we have 6 electrons left, if we were to exclude the electrons shared in the " single bonds. " This can be placed as three lone pairs on Iodine ( central atom )!
The molecular geometry can't be linear, as there are lone pairs on the atoms. This makes it bent.
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Answer : The boiling point of the resulting solution is,
Explanation :
Formula used for Elevation in boiling point :
or,
where,
= boiling point of solution = ?
= boiling point of water =
= boiling point constant =
m = molality
i = Van't Hoff factor = 1 (for non-electrolyte)
= mass of solute (sucrose) = 5.0 g
= mass of solvent (water) = 10.0 g
= molar mass of solute (sucrose) = 342.3 g/mol
Now put all the given values in the above formula, we get:
Therefore, the boiling point of the resulting solution is,