Give the number of lone pairs around the central atom and the geometry of the ion IBr2.
1 answer:
Answer:
Option E!
Explanation:
If we were to draw the lewis dot structure for IBr2 -, we would first count the total number of valence electrons ( " available electrons " ). Iodine has 7 valence electrons, and so does Bromine, but as Bromine exists in 2, the total number of valence electrons would be demonstrated below;
Don't forget the negative on the Bromine!
Now go through the procedure below;
1 ) Place Iodine in the middle and draw single bonds to each of the bromine.
2 ) Add three lone pairs on each of the Bromine's
3 ) Now we have 6 electrons left, if we were to exclude the electrons shared in the " single bonds. " This can be placed as three lone pairs on Iodine ( central atom )!
The molecular geometry can't be linear, as there are lone pairs on the atoms. This makes it bent.
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Answer:
The value of the Golden Igloo is $227.4 million.
Explanation:
First, we need to find the inner and the outer volume of the half-spherical shell:
The total volume is given by:
Where:
: is the inner volume
: is the inner radius = 1.25/2 = 0.625 m
: is the outer volume
: is the outer radius = 1.45/2 = 0.725 m
Then, the total volume of the Igloo is:
Now, by using the density we can find the mass of the Igloo:
Finally, the value (V) of the antiquity is:
Therefore, the value of the Golden Igloo is $227.4 million.
I hope it helps you!