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zheka24 [161]
3 years ago
6

A pulsar is a rapidly rotating neutron star that emits a radio beam the way a lighthouse emits a light beam. We receive a radio

pulse for each rotation of the star. The period T of rotation is found by measuring the time between pulses. Suppose a pulsar has a period of rotation of T = 0.0922 s that is increasing at the rate of 3.64 x 10-7 s/y. (a) What is the pulsar's angular acceleration
Physics
2 answers:
kow [346]3 years ago
7 0

Answer:

- 8.5 x 10^-12 rad/s²

Explanation:

Time period, T = 0.0922 s

dT / dt = 3.64 x 10^-7 s/year

As we know that

α = dω/dt

where, α is the angular acceleration and ω is the angular velocity

ω = 2π/T

\alpha =\frac{d\omega }{dt}

\alpha =\frac{d\left ( \frac{2\pi }{T} \right ) }{dt}

\alpha =-\frac{2\pi}{T^{2}}\times \frac{dT}{dt}

By substituting the values

\alpha =-\frac{2\times 3.14}{0.0922^{2}}\times \frac{3.64\times 10^{-7}}{365\times 24\times 3600}

α = - 8.5 x 10^-12 rad/s²

Elenna [48]3 years ago
6 0

Answer:

-8.54883\times 10^{-12}\ rad/s^2

Explanation:

T = Time period = 0.0922 s

\dfrac{dT}{dt}=3.64\times 10^{-7}\ s/y

Angular speed is given by

\omega=\dfrac{2\pi}{T}

Angular acceleration is given by

\alpha=\dfrac{d\omega}{dt}\\\Rightarrow \alpha=\dfrac{d\dfrac{2\pi}{T}}{dt}\\\Rightarrow \alpha=-\dfrac{2\pi}{T^2}\dfrac{dT}{dt}\\\Rightarrow \alpha=-\dfrac{2\pi}{0.0922^2}\times\dfrac{3.64\times 10^{-7}}{365.25\times 24\times 60\times 60}\\\Rightarrow \alpha=-8.52541\times 10^{-12}\ rad/s^2

The pulsar's angular acceleration is -8.52541\times 10^{-12}\ rad/s^2

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7. A force of 100 N acting on a body gives it a speed of 200 m/s in 2
alekssr [168]

Answer:

Choice a. 1 kg, assuming that all other forces on the object (if any) are balanced.

Explanation:

By Newton's Second Law,

\displaystyle a = \frac{\Sigma F}{m},

where

  • a is the acceleration of the object in \text{m}\cdot\text{s}^{-2},
  • \Sigma F is the net force on the object in Newtons, and
  • m is the mass of the object in kilograms.

As a result,

\displaystyle m = \frac{\Sigma F}{a}.

Assume that all other forces on this object are balanced. The net force on the object will be 100\;\text{N}. The net force is constant. Acceleration should also be constant and the same as the average acceleration in the two seconds.

<h3>What is the average acceleration of this object?</h3>

\displaystyle \begin{aligned}\text{Acceleration} &= \text{Average Acceleration}=\frac{\text{Change in Velocity}}{\text{Time Taken}}\end{aligned}.

\displaystyle {a} = \frac{200\;\text{m}\cdot\text{s}^{-1}}{2\;\text{s}}=100\;\text{m}\cdot\text{s}^{-2}.

<h3>Apply Newton's Second Law to find the mass of the object.</h3>

\displaystyle m = \frac{\Sigma F}{a} = \frac{100\;\text{N}}{100\;\text{m}\cdot\text{s}^{-2}} = 1\;\text{kg}.

6 0
3 years ago
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vivado [14]
Answer is C...........
5 0
2 years ago
Plzzz answer this question correctly
tekilochka [14]

Answer:

changing the direction in which a force is exerted

8 0
3 years ago
A car starts from rest and after 20 seconds it's velocity becomes 108km find the acceleration of the car
andre [41]

Answer:

1.5 km/s²

Explanation:

Given that:

a car starts from rest; it means the initial velocity (u) = 0 km/hr = 0 m/s

after time (t) = 20 seconds

the final velocity = 108 km/hr = 30 m/s

The acceleration (a) of the car can be determined by using the formula:

a = \dfrac{v-u}{t}

a = \dfrac{30\  m/s -0 \ m/s}{20 \ s}

a = \dfrac{30 \  m/s}{20 \ s}

a = 1.5 km/s²

7 0
3 years ago
A 300 kg car initially travels with a velocity of 20 m/s to the right. A net force F acts on the car for 5 s, which causes the v
hram777 [196]

Answer:

<em>600N.</em>

Explanation:

From the question, we are to calculate the net force acting on the car.

According to Newton's second law of motion:

F = ma

m is the mass of the car

a is the acceleration = change in velocity/Time

a = v-u/t

F = m(v-u)/t

v is the final velocity = 30m/s

u is the initial velocity = 20m/s

t is the time = 5secs

m = 300kg

Get the net force:

Recall that: F = m(v-u)/t

F  = 300(30-20)/5

F = 60(30-20)

F = 60(10)

<em>F = 600N</em>

<em>Hence the net force acting on the car is 600N.</em>

<em></em>

<em></em>

3 0
3 years ago
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