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zheka24 [161]
3 years ago
6

A pulsar is a rapidly rotating neutron star that emits a radio beam the way a lighthouse emits a light beam. We receive a radio

pulse for each rotation of the star. The period T of rotation is found by measuring the time between pulses. Suppose a pulsar has a period of rotation of T = 0.0922 s that is increasing at the rate of 3.64 x 10-7 s/y. (a) What is the pulsar's angular acceleration
Physics
2 answers:
kow [346]3 years ago
7 0

Answer:

- 8.5 x 10^-12 rad/s²

Explanation:

Time period, T = 0.0922 s

dT / dt = 3.64 x 10^-7 s/year

As we know that

α = dω/dt

where, α is the angular acceleration and ω is the angular velocity

ω = 2π/T

\alpha =\frac{d\omega }{dt}

\alpha =\frac{d\left ( \frac{2\pi }{T} \right ) }{dt}

\alpha =-\frac{2\pi}{T^{2}}\times \frac{dT}{dt}

By substituting the values

\alpha =-\frac{2\times 3.14}{0.0922^{2}}\times \frac{3.64\times 10^{-7}}{365\times 24\times 3600}

α = - 8.5 x 10^-12 rad/s²

Elenna [48]3 years ago
6 0

Answer:

-8.54883\times 10^{-12}\ rad/s^2

Explanation:

T = Time period = 0.0922 s

\dfrac{dT}{dt}=3.64\times 10^{-7}\ s/y

Angular speed is given by

\omega=\dfrac{2\pi}{T}

Angular acceleration is given by

\alpha=\dfrac{d\omega}{dt}\\\Rightarrow \alpha=\dfrac{d\dfrac{2\pi}{T}}{dt}\\\Rightarrow \alpha=-\dfrac{2\pi}{T^2}\dfrac{dT}{dt}\\\Rightarrow \alpha=-\dfrac{2\pi}{0.0922^2}\times\dfrac{3.64\times 10^{-7}}{365.25\times 24\times 60\times 60}\\\Rightarrow \alpha=-8.52541\times 10^{-12}\ rad/s^2

The pulsar's angular acceleration is -8.52541\times 10^{-12}\ rad/s^2

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BlackZzzverrR [31]

Answer:

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Explanation:

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s = \frac{(25\,\frac{N}{m} )\cdot (0.1\,m)^{2}}{2\cdot (0.05\,kg)\cdot (9.807\,\frac{m}{s^{2}} )\cdot \sin 25^{\textdegree}}

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s = \frac{(25\,\frac{N}{m} )\cdot (0.2\,m)^{2}}{2\cdot (0.05\,kg)\cdot (9.807\,\frac{m}{s^{2}} )\cdot \sin 25^{\textdegree}}

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2 years ago
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an 1150kg elevator moving down speeds up at a rate of 3.5m/s. what is the tension in the supporting cables?
gtnhenbr [62]

Answer:

The tension force in the supporting cables is 7245N

Explanation:

There are two forces acting on the elevator: the force of gravity pointing down (+) with magnitude (elevator mass) x (gravitational acceleration), and the tension force of the cable pointing up (-) with an unknown magnitude F. The net force is the sum of these forces:

F_{net} = F_g - F = m\cdot g - F\\

We are given the resulting acceleration along with the mass, i.e., we know the net force, allowing us to solve for F:

1150kg\cdot 3.5\frac{m}{s^2}= 1150kg \cdot 9.8\frac{m}{s^2}-F\\\implies F = 1150kg\cdot(9.8-3.5)\frac{m}{s^2}= 7245N

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3 years ago
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Answer:

On the magnitude of the charges, on their separation and on the sign of the charges

Explanation:

The magnitude of the electric force between two charges is given by

F=k\frac{q_1 q_2}{r^2}

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k is the Coulomb's constant

q1, q2 are the magnitudes of the two charges

r is the separation between the charges

From the formula, we see that the magnitude of the force depends on the following factors:

- magnitude of the two charges

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Moreover, the direction of the force depends on the sign of the two charges. In fact:

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A dart with mass md is launched toward a block of mass mb that is suspended from a string of length L. The dart is moving horizo
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Part a)

The time of interaction of the two bodies i.e the hanging mass and the stick is same. Thus, force caused by dart on the block = force caused by block on the dart. Hence, impulse is the same for both the objects.  

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H is directly proportional to the square of speed.  

Hence, the higher is the speed, the greater will be the height.  

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0.000234 seconds

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