A ball is thrown straight up with a launch of 3 m/s.

Which of these are part of the electromagnetic spectrum?

bazaltina [42]

Answer: A, C, E

Explanation:

Gamma rays, Microwaves, and Radio waves

6 0

3 years ago

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A classmate is attempting to draw a free body diagram for a box being pushed across the floor at a constant speed. The image bel

aivan3 [116]

Answer:

A. The applied force should be the same size as the friction force

Explanation:

Whenever we apply a force to an object it moves if the force applied to that object is unbalanced and there is no force or a lesser force to counter it. According to Newton's Second Law of motion, when an unbalanced force is applied to an object it produces an acceleration in the object in its own direction. So, the two forces acting on this box are the frictional force and the applied force in horizontal direction. In order to move the box at constant speed, the applied force must first, overcome the frictional force, so the object can start its motion. Since, the motion has constant velocity, it means no acceleration. So, the force must be balanced in order to avoid acceleration as a consequence of Newton's Second Law of motion. Therefore, the correction in this case will be:

<u>A. The applied force should be the same size as the friction force</u>

7 0

3 years ago

A 3874-kg rollercoaster is brought to the top of a 42m hill in 40 seconds,then drops 28m before the next hill.

Ede4ka [16]

(a) The work required to get the coaster to the top of the first hill is 1,594,538.4 J.

(b) The power required to bring the train to the top of the first hill is 39,863.46 W.

(c) The energy lost when the coaster drops is 531,512.8 J.

(d) The left at the bottom is determined as 1,063,025.6 J.

<h3>Work done to bring the rollercoaster top of the hill</h3>

W = Fn x d = mgh

W = 3874 x 9.8 x 42

W = 1,594,538.4 J

<h3>Power dissipated in bringing the rollercoaster on top hill</h3>

P = Fv

P = Fd/t

P = W/t

P = 1,594,538.4 /40 = 39,863.46 W

<h3>Energy lost when the coaster drops</h3>

E = 1,594,538.4 - (3874 x 9.8 x 28)

E = 531,512.8 J

<h3>Energy left at the bottom</h3>

E = 3874 x 9.8 x 28 = 1,063,025.6 J

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6 0

2 years ago

A solid metal object hangs from a force sensor by a thread in the open air, and the actual weight is measured to be 0.71 N. Then

Alexeev081 [22]

Answer:

The apparent weight of the object is 0.465 N.

Explanation:

Given that,

Weight = 0.71 N

Water level = 50 mL

object inserted = 75 mL

We need to calculate the volume of solid

Using formula of volume

$V=25\ ml = 25\times10^{-6}\ m^3$

We need to calculate the buoyancy force

Using formula of buoyancy force

$F'= V\rho g$

Put the value into the formula

$F'=25\times10^{-6}\times1000\times9.8$

$F'=0.245\ N$

We need to calculate the apparent weight of the object

Using formula of apparent weight

$W=F-F'$

Put the value into the formula

$W=0.71-0.245$

$W=0.465\ N$

Hence, The apparent weight of the object is 0.465 N.

5 0

3 years ago

If a 2 liter bottle of coke cost $2.34 how much does 1mL of coke cost?

Ainat [17]

1mL of coke cost =$0.00117.

The cost of 2-liter bottle of coke is $2.34

The unit of 1 liter is 1000ml.

Then the 2 liter coke bottle volume is 2000ml

The formula is ( divide the total price by the quantity).

$2.34/2000=0.00117.

The capacity of a liquid is measured in metric units of volume called liters and milliliters. There are four units of measurement for liquid volume: milliliters, centiliters, liters, and kiloliters. The values of these units vary even though they all refer to the same quantity.

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3 0

2 years ago