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3 years ago

13

During a free fall Swati was accelerating at -9.8m/s2. After 120 seconds how far did she travel? Use the formula =1/2 * t2 to so

lve your answer.

2 answers:

murzikaleks [220]3 years ago

6 0

D = 70,560 meters this is the answer need more characters there we go:)

Ulleksa [173]3 years ago

3 0

8/9 score.....................

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A plane leaves the airport in Galisteo and flies 160 km at 66.0 ∘ east of north; then it changes direction to fly 260 km at 49.0

user100 [1]

<u>The question doesn't have any particular requirement, but we'll compute the displacement of the plane from its initial and final landing point in the pasture </u>

Answer:

$\displaystyle |\vec{r}|=321.464\ km$

$\displaystyle \theta =-19.395^o$

Explanation:

<u>Displacement </u>

The vector displacement $\vec r$ is a measure of the change of position of a moving object. The displacement doesn't depend on the path followed, only on the final and initial positions. Its scalar counterpart, the distance, does measure the total space traveled and considers all the changes in the direction taken by the object. To find the displacement, we must add all the particular displacements by using vectors.

The plane first flies 160 km at 66° east of north. To find the vector expression of this displacement, we must know the angle with respect to the East direction or North of East. Knowing the angle East of North is 66°, the required angle is 90°-66°=34°

The first vector is expressed as

$\displaystyle \vec{r_1}=\left \langle 160^o\ cos34^o, 160\ sin34^o \right \rangle$

$\displaystyle \vec{r_1}=\left \langle 132.646, 89.471 \right \rangle$

The second displacement is 260 km at 49° South of East. This angle is below the horizontal respect to the reference, thus we use -49°.

The second vector is expressed as:

$\displaystyle \vec{r_2}=\left \langle 260\ cos(-49^o), 260\ sin(-49^o)\right \rangle$

$\displaystyle \vec{r_2}=\left \langle 170.575,-196.224\right \rangle$

The total displacement is computed as the vectorial sum of both vectors

$\displaystyle \vec{r}=\vec{r_1}+\vec{r_2}=\left \langle 132.646+170.575\right \rangle+ \left \langle89.471-196.224\right \rangle$

$\displaystyle \vec{r}=\left \langle 303.221,-106.753\right \rangle\ km$

The magnitude of the total displacement is

$\displaystyle |\vec{r}|=\sqrt{303.221^2+(-106,753)^2}$

$\displaystyle |\vec{r}|=321.464\ km$

And the direction is

$\displaystyle tan\ \theta =\frac{-106.753}{303.221}=-0.352$

$\displaystyle \theta =-19.395^o$

6 0

3 years ago

Which two quantities can be used to describe motion? A: Displacement and weight. B: speed and acceleration. C: speed and mass. D

HACTEHA [7]

The answer is B as all the other options contain quantities not related to describing motion

3 0

3 years ago

Please show your work.<br> 13. Convert 97 degrees fahrenheit to degrees celsius.<br> Need this now

yan [13]

Answer:

(97°F − 32) × 5/9 = 36.111°C

Explanation:Hope this helped

3 0

3 years ago

To water the yard you use a hose with a diameter of 3.2 cm. Water flows from the hose with a speed of 1.1 m/s. If you partially

cupoosta [38]

Answer:

The speed of water flow inside the pipe at point - 2 = 34.67 m / sec

Explanation:

Given data

Diameter at point - 1 = 3.2 cm

Velocity at point - 1 = 1.1 m / sec = 110 cm / sec

Diameter at point - 2 = 0.57 cm

Velocity at point - 2 = ??

We know that from the continuity equation the rate of flow is constant inside a pipe between two points.

Thus

⇒ $A_{1}$ × $V_{1}$ = $A_{2}$ × $V_{2}$

⇒ $\frac{\pi }{4}$ × $d_{1} ^{2}$ × $V_{1}$ =

⇒ $d_{1} ^{2}$ × $V_{1}$ = $d_{2} ^{2}$ × $V_{2}$

⇒ $(3.2)^{2}$ × 110 = $(0.57)^{2}$ × $V_{2}$

⇒ $V_{2}$ = 3467 cm / sec

⇒ $V_{2}$ = 34.67 m / sec

Thus the speed of water flow inside the pipe at point - 2 = 34.67 m / sec

3 0

3 years ago

A helium balloon is filled to a volume of 2.88 x 103 L at 722 mm Hg and 19Â°C. When the balloon is released, it rises to an alti

inn [45]

Answer:

V₂=4.57 x 10³ L

Explanation:

Given that

V₁= 2.88 x 10³ L

P₁=722 mm Hg

T₁ = 19°C

T₁ =292 K

P₂=339 mm Hg

T₂= - 55°C

T₂=218 K

Lets take final volume = V₂

We know that ideal gas equation

PV = m R T

By applying mass conservation

$\dfrac{P_1V_1}{RT_1}=\dfrac{P_2V_2}{RT_2}$

$\dfrac{722\times 2.88\times 10^3}{292}=\dfrac{339\times V_2}{218}$

V₂=4.57 x 10³ L

Therefore volume will be 4.57 x 10³ L

3 0

3 years ago