The gas would also decrease in size since the container lost gas to decrease the size of the container.
Answer:
Explanation:
In order to measure the coefficient of friction , we apply external force to move the body . When external force comes in motion , we adjust the external force so that it moves with zero acceleration or uniform velocity . In this case external force becomes equal to kinetic frictional force and then net force becomes zero because
net force = mass x acceleration = m x 0 = 0
Now frictional force = μ mg where μ is coefficient of kinetic friction
so F = μ mg where F is external force applied
μ = F / mg
Hence , to make external force equal to frictional force , it is necessary to make acceleration of body zero .
Answer:
30 metres.
Explanation:
Given that a red ball moves horizontally in a 30 m long tube.
Displacement is the distance travelled in a specific direction. It has both magnitude and direction.
Since the motion is horizontal, it moves is a certain direction.
Within the stipulation of time, the displacement will be the distance covered in the horizontal direction which is 30 metres.
Therefore, the displacement of the motion of the red ball is 30 metres.
<h3>
Answer:</h3>
Momentum of the given body will be : 75000 Kg m/s
<h3>
Explanation:</h3>
According to Newton's first law of motion, all bodies continue to be in the state of rest or motion unless an external force is applied on the body. We can use this in the case of momentum also
The formula of momentum is given by :

Here, we are given the mass of the body ( m ) as 3000kg and the velocity of the body ( v ) as 25 m/s. On putting the values in the formula:

Momentum is associated with the mass of the moving body and can be defined as the quantity of motion measured as a product of mass and velocity.
Answer:
Explanation:
Given
radius of circle=1.4 m
Height of stone above ground=1.5 m
Horizontal distance(R)=10 m
It is given at the time of break stone flies horizontally thus stone to cover a height of 1.5 m in time t before reaching ground

t=0.55 s
Initial horizontal velocity at the time of break is given by u


u=18.07 m/s
Therefore magnitude of centripetal acceleration is given by
