Answer:
42 km/h was the average speed of the car for its three-hour trip.
Explanation:
Diameter of the car wheel = d = 0.4 m
Radius of the car wheel = r = 0.5 d = 0.5 × 0.4 m =0.2 m
Distance covered in 1 complete revolution = 
Distance covered in 100,000 complete revolution,D = 

1 m = 0.001 km
125,663.71 m = 125,663.71 × 0.001 km = 125.66371 km
Time taken to complete 100,000 revolution by a wheel = t = 3 hours
Speed of car : S

42 km/h was the average speed of the car for its three-hour trip.
Answer:
Horizontal translation of six units
Explanation:
I would say the correct answer would be light travels faster in medium 3 then medium 2.
Answer:
a)

b)

Explanation:
L = inductance of the Inductor = 3.14 mH = 0.00314 H
C = capacitance of the capacitor = 5.08 x 10⁻⁶ F
a)
f = frequency = 55.7 Hz
Impedance is given as



b)
f = frequency = 11000 Hz
Impedance is given as



Answer:
This is as a result that about the central axis a collapsed hollow cone is equivalent to a uniform disc
Explanation:
The integration of the differential mass of the hollow right circular cone yields

and for a uniform disc
I = 1/2πρtr⁴ = 1/2Mr².