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Vlad1618 [11]
3 years ago
12

3. Compare the slope of the velocity-time graph to the average of all your acceleration values. Are they close? What does the sl

ope of a velocity (or speed) vs. time graph mean? Explain the answer using your data. How does the value of g that you calculated compare to the accepted value of 9.80 m/s2? What is your percent error? Remember that the value of g can be calculated by using g = a/sinθ and percent error can be calculated using the following equation:
Physics
1 answer:
Marina86 [1]3 years ago
6 0

The slope of a speed-time graph is the acceleration represented by the graph.

All other parts of this question refer to a lab experiment or exercise
where I was not present, but Zeesam16 was.  Therefore I have no data
with which to answer the rest of the question, and hope that Zeesam can
handle it.


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Best exercises for these topics. <br> (have the amount of exercises, have 4 exercises for each.)
Kipish [7]

Answer:

what is the question?

Explanation:

i dont understand

5 0
2 years ago
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2. If the efficiency of a device is 64 %, what is the amount of Energy lost/ wasted by this device?
Inessa05 [86]
It would be 78 becuase the 2 percent of 64 is many of energy lost
3 0
3 years ago
A flute is designed so that it plays a frequency of 261.6 Hz, middle C, when all the holes are covered and the temperature is 20
irinina [24]

Answer:

0.655 m

13.468°C

Explanation:

v = Speed of sound at 20.0°C = 343 m/s (general value)

For one both end open we have the expression

L=\dfrac{\lambda_1}{2}\\\Rightarrow L=\dfrac{\dfrac{v}{f_1}}{2}\\\Rightarrow L=\dfrac{\dfrac{343}{261.6}}{2}\\\Rightarrow L=0.655581039755\ m

The length of the flute is 0.655 m

Beat frequency is given by

\Delta f=f_1-f_2\\\Rightarrow 3=261.6-f_2\\\Rightarrow f_2=261.6-3\\\Rightarrow f_2=258.6\ Hz

Velocity of the wave is

v=f_2\lambda_1\\\Rightarrow v=258.6\times \dfrac{343}{261.6}\\\Rightarrow v=339.066513761\ m/s

The temperature is given by

T=273(\dfrac{v}{331})^2\\\Rightarrow T=273(\dfrac{339.066513761}{331})^2\\\Rightarrow T=286.468227799\ K=286.468227799-273=13.468227799^{\circ}C

The temperature of the room is 13.468°C

4 0
3 years ago
Photo below with question, please help need to confirm answer<br> Is the answer A?
GarryVolchara [31]

Answer:

Only circuit A will contain to lit bulbs

3 0
3 years ago
An object of mass 3.4 kg is moving in a straight line with kinetic energy 59.177 J. A force is applied in the direction of its m
rusak2 [61]

Answer:

Its momentum is multiplied by a factor of 1.25

Explanation:

First, we <u>calculate the initial velocity of the object</u>:

  • K = 0.5 * m * v₁²
  • 59.177 J = 0.5 * 3.4 kg * v₁²
  • v₁ = 5.9 m/s

With that velocity we can <u>calculate the initial momentum of the object</u>:

  • p₁ = v₁ * m
  • p₁ = 20.06 kg·m/s

Then we <u>calculate the velocity of the object once its kinetic energy has increased</u>:

  • (59.177 J) * 1.57 = 0.5 * 3.4 kg * v₂²
  • v₂ = 7.4 m/s

And <u>calculate the second momentum of the object</u>:

  • p₂ = v₂ * m
  • p₂ = 25.16 kg·m/s

Finally we <u>calculate the factor</u>:

  • p₂/p₁ = 1.25
3 0
2 years ago
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