3. Compare the slope of the velocity-time graph to the average of all your acceleration values. Are they close? What does the sl
1 answer:
You might be interested in
Answer:
The number of photons per second that strike the given area is 2.668 x 10⁸ photons/second
Explanation:
Given;
intensity of the sunlight, I = 2.00 kJ·s−1·m^−2
area of incident, A = 5.2 cm² = 5.2 x 10⁻⁴ m²
Energy of incident photons per second on the given area;
E = IA
E = (2000)( 5.2 x 10⁻⁴)
E = 1.04 J/s
Energy of a photon is given is by;
The number of photons per second that strike the given area is;
Therefore, the number of photons per second that strike the given area is 2.668 x 10⁸ photons/second
Answer:
Explanation:
From the question we are told that
The number of turns is
The radius is
The position from the center consider is x = 3.45 cm = 0.0345 m
The induced emf is
Generally according to Gauss law
=>
Where A is the cross-sectional area of the solenoid which is mathematically represented as
=>
=> ggl;
Here is the permeability of free space with value
=>
=>