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2 years ago

Energy conservation

Physics

1 answer:

balandron [24]2 years ago

7 0

Answer:

7.328m/s

Explanation:

Given parameters:

height of table = 0.68m

final velocity of the ball = 6m/s

Unknown:

Initial velocity of ball = ?

Solution:

To solve this problem, we are going to employ the appropriate motion equation.

We must understand that this fall occurs in the presence of gravity;

V = U + 2gH

Where;

V is the final velocity

U is the initial velocity

g is the acceleration due to gravity

H is the height of the pool table

Since U is the unknown, let us make it the subject of the expression;

U = V - 2gH

U = 6 - (2 x 9.8 x 0.68) = 7.328m/s(deceleration)

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A 42.2 kg sled is pulled forward

zaharov [31]

The net force on the sledge is 31.64N.

Frictional force = µkR

= 0.269 x 42.2 x 9.81 = 111.36

net force = 143N - 111.36N

= 31.64N

refer brainly.com/question/24557767

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7 0

2 years ago

The earth spins on its axis once a day and orbits the sun once a year (365 1/4 days). Determine the average angular velocity (in

lubasha [3.4K]

Answer:

Given that

The earth spins on its axis once a day and orbits the sun once a year (365 1/4 days)

When earth spins on its axis

We know that earth take 1 day to complete one revolution around its own axis.

T= 1 day = 24 hr = 24 x 3600 s

T=86400 s

We know that

T=2π/ω

ω= 2π/T

ω= 2π/86400

ω=7.27 x 10⁻5 rad/s

When earth revolve around earth

T =365 1/4 days = 365.25 days

T= 365.24 x 86400 s

T=31557600

We know that

T=2π/ω

ω= 2π/T

ω= 2π/31557600

ω=1.99 x 10⁻⁷ rad/s

8 0

2 years ago

Read 2 more answers

You are looking at yourself in a plane mirror, a distance of 3 meters from the mirror. your brain interprets what you are seeing

AleksandrR [38]

You are looking at yourself in a plane mirror, a distance of 3 meters from the mirror. your brain interprets what you are seeing in the mirror as being a person standing 6 meters from you.

<h3>Calculation</h3>

The plane mirror shows an exact replica of the real world. that means the distance of you from the mirror is the same distance as your reflection form the mirror at the opposite side of the mirror.

Thus, distance of image from the plane mirror is same as the distance of object (person) from the plane mirror but the image is formed behind the mirror.

Thereby we have v=u=3 m

Thus, distance between image and the person

is d = v + u = 3 + 3 = 6 m

Thus, the person is 6 meters away from the image.

To know more such mirror problems, visit:

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8 0

1 year ago

Two large rectangular aluminum plates of area 180 cm2 face each other with a separation of 3 mm between them. The plates are cha

Westkost [7]

Answer:

Φ = 361872 N.m^2 / C

Explanation:

Given:-

- The area of the two plates, $A_p = 180 cm^2$

- The charge on each plate, $q = 17 * 10^-^6 C$

- Permittivity of free space, $e_o = 8.85 * 10^-^1^2 \frac{C^2}{N.m^2}$

- The radius for the flux region, $r = 3.3 cm$

- The angle between normal to region and perpendicular to plates, θ = 4°

Find:-

Find the flux (in N · m2/C) through a circle of radius 3.3 cm between the plates.

Solution:-

- First we will determine the area of the region ( Ar ) by using the formula for the area of a circle as follows. The region has a radius of r = 3.3 cm:

$A_r = \pi *r^2\\\\A_r = \pi *(0.033)^2\\\\A_r = 0.00342 m^2$

- The charge density ( σ ) would be considered to be uniform for both plates. It is expressed as the ratio of the charge ( q ) on each plate and its area ( A_p ):

σ = $\frac{q}{A_p} = \frac{17*10^-^6}{0.018} \\$

σ = 0.00094 C / m^2

- We will assume the electric field due to the positive charged plate ( E+ ) / negative charged plate ( E- ) to be equivalent to the electric field ( E ) of an infinitely large charged plate with uniform charge density.

$E+ = E- = \frac{sigma}{2*e_o} \\\\$

- The electric field experienced by a region between two infinitely long charged plates with uniform charge density is the resultant effect of both plates. So from the principle of super-position we have the following net uniform electric field ( E_net ) between the two plates:

$E_n_e_t = (E+) + ( E-)\\\\E_n_e_t = \frac{0.00094}{8.85*10^-^1^2} \\\\E_n_e_t = 106214689.26553 \frac{N}{C} \\$

- From the Gauss-Law the flux ( Φ ) through a region under uniform electric field ( E_net ) at an angle of ( θ ) is:

Φ = E_net * Ar * cos ( θ )

Φ = (106214689.26553) * (0.00342) * cos ( 5 )

Φ = 361872 N.m^2 / C

5 0

2 years ago

PLEASE HELP

jasenka [17]

Don't over think it!

For example, if you do 5 laps in 5 minutes then you do one lap per minute. If you use that example and you apply it to your problem you'll notice that the answer is simply C. 1km/min.

Best wishes!

4 0

3 years ago

Read 2 more answers