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mylen [45]
3 years ago
9

What is 4.2 converted into grams

Physics
1 answer:
tiny-mole [99]3 years ago
3 0

Explanation:

4.2 converted to grams equal 119.067997125

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A baseball is hit with a bat. The direction of the ball is completely reversed and its speed is doubled. If the actual contact w
alexdok [17]
Before the impact, let the velocity of the baseball was v m/s.

After being hit by the bat its velocity is -2v
So, change in velocity, Deltav=v-(-2v)=3v
Acceleration is defined as the rate of change in velocity, i.e. actual change in velocity divided by the time taken to change it. Time taken to change velocity is the time of actual contact of the bat and ball, i.e. 0.31 s.

a=(Deltav)/(Deltat)
=(3v)/0.37
Therefore, a/v=3/0.31=9.7 s^-1
So, the ratio of acceleration of the baseball to its original velocity is 9.7.
8 0
4 years ago
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An object takes 5 seconds to move 2 meters upward. How fast did it go?
jonny [76]

Answer:

2.5

Explanation:

5/2=2.5

8 0
3 years ago
How does light behave when a laser is pointed at a prism?
Gnoma [55]

Answer:

So when you shine a laser through a prism, there's nothing to be separated, and the light stays together.

Explanation:

7 0
2 years ago
A force of 450 N moves a body through 300 cm in the direction of force. Calculate the work
OlgaM077 [116]

Answer:

150J

Explanation:

Formula : <u>Work</u><u> </u><u>done</u>

Force x distance

work done = force x distance

Distance should be measured in meters

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=150J

3 0
3 years ago
I have an astronomy question... Spinning up the solar nebula. The orbital speed of the material in the solar nebula at Pluto's a
attashe74 [19]
<span>The angular momentum of a particle in orbit is 

l = m v r 

Assuming that no torques act and that angular momentum is conserved then if we compare two epochs "1" and "2" 

m_1 v_1 r_1 = m_2 v_2 r_2 

Assuming that the mass did not change, conservation of angular momentum demands that 

v_1 r_1 = v_2 r_2 

or 

v1 = v_2 (r_2/r_1) 

Setting r_1 = 40,000 AU and v_2 = 5 km/s and r_2 = 39 AU (appropriate for Pluto's orbit) we have 

v_2 = 5 km/s (39 AU /40,000 AU) = 4.875E-3 km/s

Therefore, </span> the orbital speed of this material when it was 40,000 AU from the sun is <span>4.875E-3 km/s.

I hope my answer has come to your help. Thank you for posting your question here in Brainly.
</span>
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3 years ago
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