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Ahat [919]
3 years ago
7

Aunt Mary needs to hang a picture in her bedroom. She uses a hammer to drive the nail into the wall. Find the force exerted by t

he hammer on the nail if the hammer stays in contact with the nail for 0.4s and has an impulse of 32Ns.
Physics
1 answer:
Cerrena [4.2K]3 years ago
4 0

t = time of contact of hammer with the nail = 0.4 sec

I = impulse exerted by the hammer on the nail = 32 N s

F = force applied by the hammer on the nail

we know that , impulse is given as

I = F t                  where I = impulse , F = force , t = time

hence the impulse of hammer on nail is given as

I = F t

inserting the values

32 Ns = F (0.4 sec)

F = 32/0.4

F = 80 N

hence the force exerted by the hammer comes out to be 80 N


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A 0.12 g honeybee acquires a charge of +24pC while flying. The earth's electric field near the surface is typically 100 N/C, dow
shusha [124]

Answer:

150000000

\dfrac{F_e}{F_g}=0.00000203873598369

49050000 N/C

Explanation:

q = Charge = 24 pC

m = Mass of honeybee = 0.12 g

E = Electric field = 100 N/C

g = Acceleration due to gravity = 9.81 m/s²

1\ C=6.25\times 10^{18}\ electrons

Number electrons is

n=24\times 10^{-12}\times 6.25\times 10^{18}\\\Rightarrow n=150000000

The number of electrons added or removed was 150000000

Force is given by

F_e=Eq\\\Rightarrow F_e=100\times 24\times 10^{-12}\\\Rightarrow F_e=2.4\times 10^{-9}\ N

The ratio is

\dfrac{F_e}{F_g}=\dfrac{2.4\times 10^{-9}}{0.12\times 10^{-3}\times 9.81}\\\Rightarrow \dfrac{F_e}{F_g}=0.00000203873598369

The ratio is \dfrac{F_e}{F_g}=0.00000203873598369

Balancing the forces we get

Eq=mg\\\Rightarrow E=\dfrac{mg}{q}\\\Rightarrow E=\dfrac{0.12\times 10^{-3}\times 9.81}{24\times 10^{-12}}\\\Rightarrow E=49050000\ N/C

The electric field required is 49050000 N/C

4 0
4 years ago
A snowball is rolling down a hill at 4.5 m/s and accumulating snow as it goes. Its diameter begins at 0.50 m and ends at the bot
Reil [10]
To find the change in centripetal acceleration, you should first look for the centripetal acceleration at the top of the hill and at the bottom of the hill.

The formula for centripetal acceleration is:
Centripetal Acceleration = v squared divided by r

where:
v = velocity, m/s
r= radium, m

assuming the velocity does not change:

at the top of the hill:
centripetal acceleration = (4.5 m/s^2) divided by 0.25 m
                                      = 81 m/s^2

at the bottom of the hill:
centripetal acceleration = (4.5 m/s^2) divided by 1.25 m
                                      = 16.2 m/s^2

to find the change in centripetal acceleration, take the difference of the two.
change in centripetal acceleration = centripetal acceleration at the top of the hill - centripetal acceleration at the bottom of the hill

= 81 m/s^2 - 16.2 m/s^2
= 64.8 m/s^2 or 65 m/s^2
6 0
4 years ago
A bicyclist moves along a straight line with an initial velocity vo and slows downs. Which of the following the best describes t
xeze [42]

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3 0
3 years ago
Is it possible to have a net torque when all of the forces sum to zero? Explain.
nexus9112 [7]

Answer:

Yes it is possible

Explanation:

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Then the net force on the system is always zero in that case

so we will have

F - F = 0

now for the system net torque due to these forces is given by

\tau = F(r_1) + F(r_2)

here we know that

r_1, r_2 = distance of the forces from reference about which torque is measured

so here we can say that net force is zero on the system while torque is not zero

in all such case object will rotate about a fixed position with change angular speed

3 0
4 years ago
How does a parallel circuit differ from a series circuit?
8_murik_8 [283]
I think the correct answer from the choices listed above is option B. A parallel circuit differ from a series circuit in a sense that a <span>series circuit has one path for electrons, but a parallel circuit has more than one path. In a parallel circuit there two or more paths for current to flow while a series circuit only has one.</span>
5 0
3 years ago
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