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Nesterboy [21]
3 years ago
13

A charged particle moving along the x-axis enters a uniform magnetic field pointing along the z-axis. Because of an electric fie

ld along the y-axis, the charge particle does not change velocity. What is the sign of this particle
Physics
1 answer:
Furkat [3]3 years ago
5 0

Answer:

Explanation:

Let the charge particle have charge equal to +q .

force due to electric field will be along the field that is along y - axis . To balance it force by magnetic force must be along   - y axis. ( negative of y axis )

force due to magnetic field = q ( v x B ) , v is velocity and B is magnetic field.

F = q ( v i x B k )  , ( velocity is along x direction and magnetic field is along z axis. )

= (Bqv) - j  

= - Bqv j

The force will be along - ve y - direction .

If we take charge as negative or - q

force due to electric field will be along - y axis .

magnetic force = F = -q ( v i x B k )

= +  Bqv j

magnetic force will be along  + y axis

So it is difficult to find out the nature of charge on the  particle from this experiment.

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Answer and Explanation:

Bernoulli's Principle deals with Fluid dynamics and fluid includes both liquid and gas.

The Principle gives an inverse relation between the speed or velocity of the fluid and the pressure of the fluid. It gives the speed or velocity of the liquid over varying pressure.

Bernoulli's Principle states that for a given fluid,the low pressure region will have high speed or velocity and high pressure region will have low speed or velocity

4 0
3 years ago
Two steel guitar strings have the same length. String A has a diameter of 0.513 mm and is under 403 N of tension. String B has a
Mnenie [13.5K]

Answer:

\frac{v_{A}}{v_{B}} = 1.785

Explanation:

T_{A} = Tension force in string A = 403 N

T_{B} = Tension force in string B = 800 N

d_{A} = diameter of string A = 0.513 mm

d_{B} = diameter of string B = 1.29 mm

v_{A} = wave speed of string A

v_{B} = wave speed of string B

Ratio of the wave speeds is given as

\frac{v_{A}}{v_{B}} = \sqrt{\frac{T_{A}}{T_{B}}} \left ( \frac{d_{B}}{d_{A}} \right )

\frac{v_{A}}{v_{B}} = \sqrt{\frac{403}{800}} \left ( \frac{1.29}{0.513} \right )

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5 0
3 years ago
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Answer: 14.122 units

Explanation:

We have the following vector:

\vec{V}=(x,y,z)=(8.8, 7.4, 8.2)

If we want to find its magnitude we have to use the following formula:

V=\sqrt{x^{2}+y^{2}+z^{2}}

V=\sqrt{(8.8units)^{2}+(7.4units)^{2}+(8.2 units)^{2}}

V=14.122 units  This is the magnitude of vector \vec{V}

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Leni [432]

Answer:

p = 0.16 kgm/s

Explanation:

the initial momentum combined of the two cars and the final momentum of the paired cares are the same, so we just need to find the initial momentum

p = m1v1 + m2v2

p = 0.04*4 + 0.04*0

p = 0.04*4

p = 0.16 kgm/s

7 0
3 years ago
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