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mylen [45]
3 years ago
14

PLEASE HELP !!!

Physics
1 answer:
emmainna [20.7K]3 years ago
3 0

Answer and Explanation:

The answer is <u>D) Alpha and Gamma</u>

Gamma radiation does not cause transmutations.

A <u>transmutation</u> is the <u>conversion of an atom of one element to an atom of another. This generally occurs through nuclear reacting.</u>

There are three main types of radiation: alpha, beta, and gamma. Both beta and alpha decay cause changes to the mass and atomic numbers. This results in a transmutation. Gamma radiation, however, does not.

Gamma radiation is the result of a gamma ray. In essence, the nucleus emits a high-energy proton. This is very penetrating and can only be stopped by aluminum, lead, soil, water, and concrete. This type of radiation does not change the element and, therefore, does not cause a transmutation.

<em><u>#teamtrees #PAW (Plant And Water)</u></em>

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No matter what values of m and k you used for the spring, what is the ratio of the period to k m.
Leto [7]

The relationship between the period of an oscillating spring and the attached mass determines the ratio of the period to \sqrt{\dfrac{m}{k} }.

Response:

  • The ratio of the period to  \sqrt{\dfrac{m}{k} } is always approximately<u> 2·π : 1</u>

<u />

<h3>How is the value of the ratio of the period to \sqrt{\dfrac{m}{k} } calculated?</h3>

Given:

The relationship between the period, <em>T</em>, the spring constant <em>k</em>, and the

mass attached to the spring <em>m</em> is presented as follows;

T =  \mathbf{2 \cdot \pi \cdot \sqrt{\dfrac{m}{k} }}

Therefore, the fraction of of the period to \sqrt{\dfrac{m}{k} }, is given as follows;

\mathbf{\dfrac{T}{ \sqrt{\dfrac{m}{k} }}} = 2 \cdot \pi

2·π ≈ 6.23

Therefore;

T :{ \sqrt{\dfrac{m}{k} }} = 2 \cdot \pi : 1

Which gives;

  • The ratio of the period to  \sqrt{\dfrac{m}{k} } is always approximately<u> 2·π : 1</u>

Learn more about the oscillations in spring here:

brainly.com/question/14510622

7 0
3 years ago
How much energy (in Joules) is released when 12.0 g of water cools from 20.0 °C to 11.0 °C? This is a grade 10 question from the
KATRIN_1 [288]

Answer: - 452.088joule

Explanation:

Given the following :

Mass of water = 12g

Change in temperature(Dt) = (11 - 20)°C = - 9°C

Specific heats capacity of water(c) = 4.186j/g°C

Q = mcDt

Where Q = quantity of heat

Q = 12g × 4.186j/g°C × - 9°C

Q = - 452.088joule

7 0
3 years ago
A block of mass m moving due east at speed v collides with and sticks to a block of mass 2m that is moving at the same speed vv
lapo4ka [179]

Answer:

30.36°

Explanation:

By using linear momentum; linear momentum can be expressed by the relation:

mv_xi + mv_yj

where ;

m= mass

v_x = velocity of components in the x direction

v_y = velocity of components in the y direction

If we consider the east as the positive x and north as positive y which is synonymous to what we usually have on a graph.

Then;

Initial momentum = mvi + 2mvcos 45i + 2mvsin45 j

= (mv+2mvcos45)i + (2mvsin45)j

However, the masses stick together after collision and move with a common velocity: V_xi +V_yj

∴ Final momentum = 3mv (V_xi +V_yj)

= 3mV_xi + 3mV_yj

From the foregoing ;

initial momentum = final momentum

3mV_xi + 3mV_yj = (mv+2mvcos45)i+(2mvsin45j)

So;

3mV_x = mv + 2mv cos 45 \\\\3mV_y = 2mV sin 45

V_x = \frac{mv+2mvcos45 }{3m}\\\\V_x = \frac{v+2vcos45}{3}

V_y = \frac{2mvsin45}{3m} \\\\V_y = \frac{2vsin45}{3}

Finally;

The required angle θ = tan^{-1} = \frac{V_y}{V_x}

θ = tan^{-1} = \frac{\frac{2vsin45}{3}}{\frac{v+2v.cos45}{3}}

θ = tan^{-1} = \frac{2sin 45}{1+2cos45}\\\\

θ = 30.36°

7 0
3 years ago
Pleassssssssse answerrrrrrrrrrrrrr How can you make electricity with a magnet? *
Contact [7]

Answer:

Spin a coil of wire inside a magnetic field or move a magnet inside a coil of wire.

Explanation:

This is according to Faraday's law of electromagnetic induction.

8 0
3 years ago
What is a magnetic field?
monitta
A magnetic field is charged electricity acting in the forced of magnatism
4 0
3 years ago
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