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pshichka [43]
3 years ago
12

Which types of muscle enables your stomach to produce a churning sound

Physics
1 answer:
SVETLANKA909090 [29]3 years ago
6 0
In voluntay smoth tissue muscles
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Michael is playing with two horseshoe magnets. He is trying to get them to touch, but they will not regardless of how hard he tr
Nesterboy [21]
Since like poles repel, the two horseshoe magnets have like poles facing each other, hence they repel each other and therefore they will not come in contact
8 0
3 years ago
Read 2 more answers
Q1:A large tank is filled with water. The pressure on the base of the fish tank is 4000N/m². The base of the tank is a rectangle
Ymorist [56]

Answer:

F = 36 kN

Explanation:

It is given that,

The pressure on the base of the fish tank is 4000N/m².

The base of the tank is a rectangle measuring 2.0m by 4.5m.

Area of the base of the tank is 9 m²

We need to find the force on the base caused by the base of the water. Pressure on the base of the tank is given by the force acting per unit area such that,

P=\dfrac{F}{A}\\\\F=P\times A\\\\F=4000\times 9\\\\F=36000\ N\\\\F=36\ kN

So, the force of 36 kN is acting on the base by the base of water.

7 0
3 years ago
A baseball bat is 32 inches (81.3 cm) long and has a mass of 0.96 kg. Its center of mass is 22 inches (55.9 cm) from the handle
s344n2d4d5 [400]

Answer:

0.24 kgm²

Explanation:

L = length of the bat = 81.3 cm = 0.813 m

m  = mass of the bat = 0.96 kg

d  = distance of the center of mass of bat from the axis of rotation = 55.9 cm = 0.559 m

T  = Period of oscillation = 1.35 sec

I = moment of inertia of the bat

Period of oscillation is given as

T = 2\pi \sqrt{\frac{I}{mgd}}

1.35 = 2(3.14) \sqrt{\frac{I}{(0.96)(9.8)(0.559)}}

I = 0.24 kgm²

6 0
3 years ago
A box with sides of length 40 cm is made up of six pieces of concrete of thickness 5 mm. The inside of the box is filled with 10
Damm [24]

Answer:

d)2.13 C s⁻¹

Explanation:

Rate of flow of heat through walls

=\frac{KA(T_2-T_1)}{d}

K = .33

A = 6 X .4 X .4 =0.96

T₂-T₁ = 30+40 = 70

d = 5 x 10⁻³

Put these data in the relation above

Rate of flow of heat

= \frac{.33\times.96\times70}{5\times10^{-3}}

= 4435.2 Js⁻¹

Specific heat of gas = 2.5 R = 20.785 J

Rise in temp = \frac{4435.2}{100\times20.785}

= 2.13 degree celsius.

4 0
3 years ago
A 6.0-μF air-filled capacitor is connected across a 100-V potential source (a battery). After the battery fully charges the capa
Dovator [93]

Answer:

Change in Q = 2.1x 10^-3 C

Explanation:

We are given that

The Initialcapacitance C1 = 6.0μF

Initial charge oncapacitor

Q1 = C1 V

= 6.00 x 10^-6 x 100

= 6.00 x 10^-4 C

So the Final capacitance C2 will be

= K x C1 = 4.5 x 6.00 x 10^-6

= 2.7 x 10^ -5 F

So to get Finalcharge

We use Q2 = C2 x V

= 2.7 x 10^ - 5 x 100

= 27 x 10^ -4 C

So Charge flown in thecapacitor is change in Q

Which is = Q2 - Q1

= 27 x 10^-4 - 6.0 x 10^ -4

Change in Q = 2.1x 10^-3 C

5 0
3 years ago
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