Since like poles repel, the two horseshoe magnets have like poles facing each other, hence they repel each other and therefore they will not come in contact
Answer:
F = 36 kN
Explanation:
It is given that,
The pressure on the base of the fish tank is 4000N/m².
The base of the tank is a rectangle measuring 2.0m by 4.5m.
Area of the base of the tank is 9 m²
We need to find the force on the base caused by the base of the water. Pressure on the base of the tank is given by the force acting per unit area such that,

So, the force of 36 kN is acting on the base by the base of water.
Answer:
0.24 kgm²
Explanation:
= length of the bat = 81.3 cm = 0.813 m
= mass of the bat = 0.96 kg
= distance of the center of mass of bat from the axis of rotation = 55.9 cm = 0.559 m
= Period of oscillation = 1.35 sec
= moment of inertia of the bat
Period of oscillation is given as


= 0.24 kgm²
Answer:
d)2.13 C s⁻¹
Explanation:
Rate of flow of heat through walls
=
K = .33
A = 6 X .4 X .4 =0.96
T₂-T₁ = 30+40 = 70
d = 5 x 10⁻³
Put these data in the relation above
Rate of flow of heat
= 
= 4435.2 Js⁻¹
Specific heat of gas = 2.5 R = 20.785 J
Rise in temp = 
= 2.13 degree celsius.
Answer:
Change in Q = 2.1x 10^-3 C
Explanation:
We are given that
The Initialcapacitance C1 = 6.0μF
Initial charge oncapacitor
Q1 = C1 V
= 6.00 x 10^-6 x 100
= 6.00 x 10^-4 C
So the Final capacitance C2 will be
= K x C1 = 4.5 x 6.00 x 10^-6
= 2.7 x 10^ -5 F
So to get Finalcharge
We use Q2 = C2 x V
= 2.7 x 10^ - 5 x 100
= 27 x 10^ -4 C
So Charge flown in thecapacitor is change in Q
Which is = Q2 - Q1
= 27 x 10^-4 - 6.0 x 10^ -4
Change in Q = 2.1x 10^-3 C