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2 years ago

The density of silver is 10.5 g cm3. a piece of silver with a mass of 61.3 g would ovvupy a volume of ?

1 answer:

7 0

The relationship between mass m, volume V and density d is:
$d= \frac{m}{V}$
The silver has density $d=10.5 g/cm^3$ , and the mass of the piece of silver is $m=61.3 g$ . Therefore we can calculate its volume using the previous formula:
$V= \frac{m}{d}= \frac{61.3 g}{10.5 g/cm^3}=5.84 cm^3$

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A juggler throws a ball straight up into the air. The ball remains in the air for a time (t) before it lands back in the juggler

natka813 [3]

Answer:

$9.8 m/s^2$ , downward

Explanation:

There is only one force acting on the ball during its motion: the force of gravity, which is given by

$F=mg$

where

m is the mass of the ball

$g=9.8 m/s^2$ is the acceleration of gravity (downward)

According to Newton's second law,

$F=ma$

where F is the net force on the object and a is its acceleration. Rearranging for a,

$a=\frac{F}{m}$

As we said, the only force acting on the ball is gravity, so F = mg and the acceleration of the ball is:

$a=\frac{mg}{m}=g$

Therefore, the ball has a constant acceleration of $9.8 m/s^2$ downward for the entire motion.

5 0

2 years ago

Two vectors are given by a = 8.6i + 5.1 j and b = 931 + 9.5.

skelet666 [1.2K]

Answer:

Assuming b = 9.3i + 9.5j (b = 931 + 9.5 is wrong):

a) a×b = 34.27k

b) a·b = 128.43

c) (a + b)·b = 305.17

d) The component of a along the direction of b = 9.66

Explanation:

Assuming b = 9.3i + 9.5j (b = 931 + 9.5 is wrong) we can proceed as follows:

a) The vectorial product, a×b is:

$a \times b = (8.6*9.5 - 5.1*9.3)k = 34.27k$

b) The escalar product a·b is:

$a\cdot b = (8.6*9.3) + (5.1*9.5) = 128.43$

c) Asumming (a + b)·b instead a+b·b we have:

$(a + b)\cdot b = [(8.6 + 9.3)i + (5.1 + 9.5)j]\cdot (9.3i + 9.5j) = (17.9i + 14.6j)\cdot (9.3i + 9.5j) = 305.17$

d) The component of a along the direction of b is:

$a*cos(\theta) = \frac{a\cdot b}{|b|} = \frac{128.43}{\sqrt{9.3^{2} + 9.5^{2}}} = 9.66$

I hope it helps you!

5 0

3 years ago

A Michelson interferometer uses light from a sodium lamp. Sodium atoms emit light having wavelengths 589.0 nm and 589.6 nm. The

DIA [1.3K]

The distance mirror M2 must be moved so that one wavelength has produced one more new maxima than the other wavelength is;

L = 57.88 mm

We are given;

Wavelength 1; λ₁ = 589 nm = 589 × 10⁻⁹ m

Wavelength 2; λ₂ = 589.6 nm = 589.6 × 10⁻⁹ m

We are told that L₁ = L₂. Thus, we will adopt L.

Formula for the number of bright fringe shift is;

m = 2L/λ

Thus;

For Wavelength 1;

m₁ = 2L/(589 × 10⁻⁹)

For wavelength 2;

m₂ = 2L/(589.6)

Now, we are told that one wavelength must have produced one more new maxima than the other wavelength. Thus;

m₁ - m₂ = 2

Plugging in the values of m₁ and m₂ gives;

(2L/589) - (2L/589.6) = 2

divide through by 2 to get;

L[(1/589) - (1/589.6)] = 1

L(1.728 × 10⁻⁶) = 1

L = 1/(1.728 × 10⁻⁶)

L = 578790.67 nm

L = 57.88 mm

Read more at; brainly.com/question/17161594

8 0

1 year ago

QUICK!! What class of leer is shown below?

wlad13 [49]

Answer:

3rd class lever

HOPE IT HELPS YOU OUT PLEASE MARK IT AS BRAINLIEST AND FOLLOW ME PROMISE YOU TO FOLLOW BACK ON BRAINLY.IN

5 0

2 years ago

Read 2 more answers

Two light waves, initially emitted in phase, will interfere constructively with maximum amplitude if the path-length difference

777dan777 [17]

Two light waves will interfere constructively if the path-length difference between them is a whole number.

<h3>SUPERPOSITION</h3>

The principle of superposition state that, when two or more waves meet at a point, the resultant displacement at that point is equal to the sum of the displacements of the individual waves at that point.

Interference of waves can either be constructive, or destructive.

The two light waves, initially emitted in phase, will interfere constructively with maximum amplitude if the path-length difference between them is a whole number of wavelenght 1λ, 2λ, 3λ, 4λ etc

The equivalent phase differences between the waves will be 2 $\pi$ or 360 degrees, 4 $\pi$ or 720 degrees, 6 $\pi$ 1080 degrees etc

Therefore, the two light waves, initially emitted in phase, will interfere constructively with maximum amplitude if the path-length difference between them is a whole number.

Learn more about Interference here: brainly.com/question/25310724

8 0

1 year ago