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Ymorist [56]
3 years ago
13

What is a substance ?????

Physics
1 answer:
SpyIntel [72]3 years ago
6 0
Substance is some matter (it can be solid liquid or gas) that has its own properties.. everything in this world are substances...
like for example: the bread that we consume has - wheat ..yeast.. sugar.. salt or some other substances
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Graph the following data on the graph, then use the graph to determine the half-life of this isotope.
Harlamova29_29 [7]

Answer:

4, 56

Explanation:

Hope this helped!

7 0
2 years ago
A 2cm length of wire centered on the origin carries a 20A current directed in the positive y direction. Determine the magnetic f
skad [1K]

Answer:

The magnetic field at a distance x = 5 m is 1.59 nT

Explanation:

Length of the wire, L = 2 cm = 0.02 m

Current, I = 20 A

x = 5 m

Magnetic field at a distance x = 5 m due to an infinitely long wire is given by:

B = \frac{\mu_{o}IL}{4\pi x\sqrt{x^{2} + L^{2}}}

B = \frac{4\pi\times 10^{- 7}\times 20\times 0.02}{4\pi \times 5\sqrt{5^{2} + 0.02^{2}}} = 1.59\times 10^{- 9}\ T

3 0
3 years ago
The ratio of red to blue marbles in a bag 3:2. If there are 18 red marbles. How many blue marbles are in the bag
Setler79 [48]
There are 12 blue marbles, because this can basically be modeled as 3/2 = 18/x, which can be solved by mutiplying 3 and 2 by 6
4 0
4 years ago
If the initial upward speed of the ball in Activity 7 C.2 is 10m/s, and the ball is releasedat a height of 1.5 m above the oor,
Ulleksa [173]

Answer:

6.5 m above the floor and 5 m above Christine's hand when it reaches the maximum height.

Explanation:

Let g = 10 m/s2 be the gravitational deceleration that affects the ball vertical motion so it comes to the maximum height at 0 speed. We can use the following equation of motion to find out the distance traveled by the ball from where it's thrown:

v^2 - v_0^2 = 2g\Delta s

where v = 0 m/s is the final velocity of the ball when it reaches maximum level, v_0 = 10m/s is the initial velocity of the ball when it starts, g = -10 m/s2 is the deceleration, and \Delta s is the distance traveled, which we care looking for:

0^2 - 10^2 = -2*(-10)\Delta s

\Delta s = 100 / (2 * 10) = 5 m

So the ball is 5 m above Christine' hands when it reaches maximum height, and since the hand is 1.5 m above the floor, the ball is 5 + 1.5 = 6.5 m above the floor when it reaches maximum height.

5 0
3 years ago
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Enter the expression 2cos2(θ)−1, where θ is the lowercase Greek letter theta.
vlabodo [156]
GAVNSTVVHUYCZ swffggff
4 0
3 years ago
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