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3 years ago

What is a substance ?????

1 answer:

6 0

Substance is some matter (it can be solid liquid or gas) that has its own properties.. everything in this world are substances...
like for example: the bread that we consume has - wheat ..yeast.. sugar.. salt or some other substances

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The spring of a spring balance is 6.0 in. long when there is no weight on the balance, and it is 8.4 in. long with 4.0 lb hung f

Sergeeva-Olga [200]

Answer:

W = 55.12 J

Explanation:

Given,

Natural length = 6 in

Force = 4 lb, stretched length = 8.4 in

We know,

F = k x

k is spring constant

4 = k (8.4-6)

k = 1.67 lb/in

Work done to stretch the spring to 10.1 in.

$W =k\int_{6}^{10.1} x$

$W = \dfrac{k}{2}[x^2]_6^{10.1}$

$W = \dfrac{1}{2}\times 1.67\times (10.1^2-6.0^2)$

W = 55.12 J

Work done in stretching spring from 6 in to 10.1 in is equal to 55.12 J.

3 0

3 years ago

Chris is about to do an experiment

Shkiper50 [21]

Answer:

Epic I guess

Explanation:

7 0

3 years ago

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Line segment Q R , Line segment R S and Line segment S Q are midsegments of Î"WXY. Triangle R Q S is inside triangle X Y W. Poin

Whitepunk [10]

The perimeter of ΔWXY is : ( D ) 14.5 cm

Calculating the perimeter of ΔWXY

QR = WY / 2

RS = XW / 2

QS = XY / 2

Given that : QR = 2.93 cm , RS = 2.04 cm, QS = 2.28 cm

Therefore

Perimeter of ΔWXY = ∑ WY + XW + XY

= 2SR + 2QS + 2QR

= 2(2.04) + 2(2.28) + 2(2.93)

= 14.5 cm

Hence we can conclude that the perimeter of ΔWXY = 14.5 cm

learn more about perimeter calculations : brainly.com/question/24744445

8 0

3 years ago

Read 2 more answers

What is the maximum kinetic energy of ejected electrons when photons of wavelength 300 nm hit a metal that has a work function o

Sonja [21]

Explanation:

Given that,

Wavelength of the photon, $\lambda=300\ nm=3\times 10^{-7}\ m$

Work function of the metal, $\phi=1.13\ eV=1.81\times 10^{-19}\ J$

We need to find the maximum kinetic energy of the ejected electrons. It can be calculated using Einstein's photoelectric equation as :

$hf=E_k+\phi$

$E_k=hf-\phi$

$E_k=h\dfrac{c}{\lambda}-\phi$

$E_k=6.63\times 10^{-34}\times \dfrac{3\times 10^8}{3\times 10^{-7}}-1.81\times 10^{-19}$

$E_k=4.82\times 10^{-19}\ J$

$E_k=3.01\ eV$

$E_k=3\ eV$

So, the maximum kinetic energy of the ejected electrons is 3 ev. Hence, this is the required solution.

3 0

3 years ago

As a car accelerates its tires increase their angular velocity from 114 rad/s to 131 rad/s in 0.43 seconds. What is the angular

e-lub [12.9K]

I think it's 39.53

(please do calculate it. I am not completely sure)

5 0

3 years ago

Read 2 more answers