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pickupchik [31]
2 years ago
14

When a potassium atom reacts with bromine, the potassium atom will

Chemistry
2 answers:
GenaCL600 [577]2 years ago
6 0
The potassium will lose an electron and the bromine will gain one. This works because it gives them both a noble gas base, which is extremely stable.

For future reference, these are the most common stable configurations: Noble Gas Core (far right on periodic table), half filled shells, empty shells, and eright electrons in a D electron cloud (transition metals, aka b section or numbers 3 - 12 on modern tables)
Firdavs [7]2 years ago
3 0

Answer: Option (a) is the correct answer.

Explanation:

An ionic bond is generally formed by a metal and a non-metal de to transfer of electrons from metal to the non-metal.

For example, potassium is an alkali metal with atomic number 19 and its electronic distribution is 2, 8, 8, 1.

And, bromine is a non-metal with atomic number 35 and it has 7 valence electrons.

So, in order to complete their octet potassium needs to lose an electron and bromine needs to gain an electron.

Hence, both of them on chemically combining together results in the formation of an ionic compound that is, potassium bromide (KBr).

Thus, we can conclude that when a potassium atom reacts with bromine, the potassium atom will lose only 1 electron.

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A 7.27-gram sample of a compound is dissolved in 250. grams of benzene. The freezing point of this solution is 1.02°C below that
UkoKoshka [18]

Answer:

The correct answer is 146 g/mol

Explanation:

<em>Freezing point depression</em> is a colligative property related to the number of particles of solute dissolved in a solvent. It is given by:

ΔTf = Kf x m

Where ΔTf is the freezing point depression (in ºC), Kf is a constant for the solvent and m is the molality of solution. From the problem, we know the following data:

ΔTf = 1.02ºC

Kf = 5.12ºC/m

From this, we can calculate the molality:

m = ΔTf/Kf = 1.02ºC/(5.12ºC/m)= 0.199 m

The molality of a solution is defined as the moles of solute per kg of solvent. Thus, we can multiply the molality by the mass of solvent in kg (250 g= 0.25 kg) to obtain the moles of solute:

0.199 mol/kg benzene x 0.25 kg = 0.0498 moles solute

There are 0.0498 moles of solute dissolved in the solution. To calculate the molar mass of the solute, we divide the mass (7.27 g) into the moles:

molar mass = mass/mol = 7.27 g/(0.0498 mol) = 145.9 g/mol ≅ 146 g/mol

<em>Therefore, the molar mass of the compound is 146 g/mol </em>

6 0
3 years ago
A flask holds 3.01 x 1023 molecules of carbon dioxide. The container is holding ________
sammy [17]
 (B), because 1.0 moles would be 6.02 x 10^23 molecules. So you have half a mole.<span>
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Can sedimentation and decantation be used for all types of mixtures? Explain
Bumek [7]

Explanation:

1. Sedimentation and decantation cannot be used for all types of mixtures.

Decantation is a separation technique in which is used to separate immiscible liquids or mixtures containing liquid and solids within them.

In decantation, gravity is used to bring the denser materials to settle at the bottom.

For homogenous mixtures, it is not possible to use decantation. A solution of sugar and water will not decant.

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The higher the mass, the faster the rate of settling. Also, as we know, mass is directly proportional to density. A body with a high density will settle faster in solution.

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