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Mila [183]
2 years ago
11

According to newton's law of gravitation, what affects the force of attraction between two objects? distance between them angle

between them their shape their color
Physics
1 answer:
OlgaM077 [116]2 years ago
3 0

The force of attraction between two objects Mass and distance.

<h3>What is newton's law of gravitation?</h3>

Every particle in the cosmos attracts every other particle with a force that is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centres, according to Newton's law of universal gravitation.

Inductive reasoning, as described by Isaac Newton, was used to deduce this general physical law from actual facts. It was created by Newton and is a component of classical mechanics. Philosophiae Naturalis Principia Mathematica, also known as "the Principia," was originally published on July 5, 1687. In April 1686, when Newton gave Book 1 of the unpublished book to the Royal Society, Robert Hooke said that Newton had learned the inverse square law from him.

According to the law, every point mass attracts every other point mass when a force applies along the line that intersects the two points, in today's parlance. The force is inversely equal to the square of the separation between the masses and directly proportional to their product.

F = G\frac{m_{1} m_{2}}{r^{2}  }

to learn more about newton's law of gravitation go to - brainly.com/question/9373839

#SPJ4

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Answer:

They are both placed at high vantage points for an optimal experience.

Explanation:

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2 years ago
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A photon of red light (wavelength = 710 nm) and a ping-pong ball (mass = 2. 40 × 10^-3 kg) have the same momentum. At what speed
Paha777 [63]

The speed of the ball moving is

v = 3.94 \times 10 {}^{ - 25}m/s

what is momentum?

The momentum p of a classical object of mass m and velocity v is given by pclassical =mv.

For photons with wavelength λ,this equation does not hold.Instead, the momentum of the Photon is given by p Photon = h/λ

where,h is the planck's constant.

The momentum of the red Photon is

given:

h = 6.626 \times 10 {}^{ - 34}kgm {}^{2}/s(plancks \: constant)

λ = 700 \times 10 {}^{ - 9} m(photons \: wavelength)

p \: photons =  \frac{6.626 \times 10 {}^{ - 34}kgm {}  ^{2}/s }{700 \times 10 {}^{ - 9}m  }

= 9.47 \times 10 {}^{ - 28}kgm /s

since,the Photon and the ping-pong ball have the same momentum,we have

pball = pphotons =  \frac{6.626 \times 10 {}^{ - 34}kgm/s  }{700 \times 10 {}^{ - 9} }

pball = mv,m = 2.40 \times 10 {}^{ - 3}kg

v = 3.94 \times 10 {}^{ - 25} m/s

Therefore, if the red photon and the ping-pong ball have the same momentum, the ping-pong ball must have a speed of approximately

v = 3.94 \times 10 {}^{ - 25}m/s

learn more about momentum of photon from here: brainly.com/question/28197406

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3 0
2 years ago
Republicans are called the Liberal Party while the Democrats are called Conservative Party.
Fudgin [204]

Answer:

Explanation:

False

5 0
3 years ago
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If the car travels thrice(3times) around the track,who much is the total distance covered?​
Katyanochek1 [597]
What does thrice mean not being mean or anything just saying so I can help with the question
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3 years ago
If a nearsighted person has a far point df that is 3.50 m from the eye, what is the focal length f1 of the contact lenses that t
Anastaziya [24]

Answer:

f1 = -3.50 m

Explanation:

For a nearsighted person an object at infinity must be made to  appear  to be at his far point which is 3.50 m away. The image of an object at infinity must be formed on the same side of the lens as the object.

∴ v = -3.5 m

Using mirror formula,

i/f1 = 1/v + 1/u

Where f1 = focal length of the contact lens, v = image distance = -3.5 m, u =         object distance = at infinity(∞) = 1/0

∴ 1/f1 = (1/-3.5) + 1/infinity

  Note that, 1/infinity = 1/(1/0) = 0/1 =0.

∴ 1/f1 = 1/(-3.5) + 0

  1/f1 = 1/(-3.5)

Solving the equation by finding the inverse of both side of the equation.

∴ f1 = -3.50 m

 Therefore a converging lens of focal length  f1 = -3.50 m

would be needed by the person to see an object at infinity clearly

8 0
3 years ago
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