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Mila [183]
2 years ago
11

According to newton's law of gravitation, what affects the force of attraction between two objects? distance between them angle

between them their shape their color
Physics
1 answer:
OlgaM077 [116]2 years ago
3 0

The force of attraction between two objects Mass and distance.

<h3>What is newton's law of gravitation?</h3>

Every particle in the cosmos attracts every other particle with a force that is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centres, according to Newton's law of universal gravitation.

Inductive reasoning, as described by Isaac Newton, was used to deduce this general physical law from actual facts. It was created by Newton and is a component of classical mechanics. Philosophiae Naturalis Principia Mathematica, also known as "the Principia," was originally published on July 5, 1687. In April 1686, when Newton gave Book 1 of the unpublished book to the Royal Society, Robert Hooke said that Newton had learned the inverse square law from him.

According to the law, every point mass attracts every other point mass when a force applies along the line that intersects the two points, in today's parlance. The force is inversely equal to the square of the separation between the masses and directly proportional to their product.

F = G\frac{m_{1} m_{2}}{r^{2}  }

to learn more about newton's law of gravitation go to - brainly.com/question/9373839

#SPJ4

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Block B has mass 6.00 kg and sits at rest on a horizontal, frictionless surface. Block A has mass 2.50 kg and sits at rest on to
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Explanation:

Block A sits on block B and force is applied on block A . Block A will experience two forces 1) force P and 2 )  friction force in opposite direction of motion . Block B will experience one force that is force of friction in the direction of motion .

Let force on block A be P . friction force on it will be equal to kinetic friction, that is μ mg , where μ is coefficient of friction and m is mass of block A

friction force = .4 x 2.5 x 9.8

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A small current element carrying a current of I = 1.00 A is placed at the origin given by d → l = 4.00 m m ^ j Find the magnetic
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Answer:

the magnitude and direction of d → B on the x ‑axis at x = 2.50 m is -6.4 × 10⁻¹¹T(Along z direction)

the magnitude and direction of d → B on the z ‑axis at z = 5.00 m is 1.6 × 10⁻¹¹T(Along x direction)

Explanation:

Use Biot, Savart, the magnetic field

d\bar{B}=\frac{U}{4\pi } \frac{i(d\bar{l}\times r)}{r^2}

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i = 1.00A

d → l = 4.00 m m ^ j

r = 2.5m

Displacement vector is

\bar{r}=x\hat i+y\hat j+z \hat k\\

\bar{r}= (2.5m) \hat i +(0m)^2 + (0m)^2

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r = \sqrt{(2.5)^2 + (0)^2 + (0)^2}

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\hat r =\frac{\bar{r}}{r}

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B)r = 5.00m

Displacement vector is

\bar{r}=x\hat i+y\hat j+z \hat k\\

\bar{r}= (5.00m) \hat i +(0m)^2 + (0m)^2

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r = \sqrt{(5.00)^2 + (0)^2 + (0)^2}

r = 5.00m

And unit vector

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Therefore, the magnetic field is as follow

d\bar{B}=\frac{U}{4\pi } \frac{i(d\bar{l}\times r)}{r^2}

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