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Mila [183]
2 years ago
11

According to newton's law of gravitation, what affects the force of attraction between two objects? distance between them angle

between them their shape their color
Physics
1 answer:
OlgaM077 [116]2 years ago
3 0

The force of attraction between two objects Mass and distance.

<h3>What is newton's law of gravitation?</h3>

Every particle in the cosmos attracts every other particle with a force that is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centres, according to Newton's law of universal gravitation.

Inductive reasoning, as described by Isaac Newton, was used to deduce this general physical law from actual facts. It was created by Newton and is a component of classical mechanics. Philosophiae Naturalis Principia Mathematica, also known as "the Principia," was originally published on July 5, 1687. In April 1686, when Newton gave Book 1 of the unpublished book to the Royal Society, Robert Hooke said that Newton had learned the inverse square law from him.

According to the law, every point mass attracts every other point mass when a force applies along the line that intersects the two points, in today's parlance. The force is inversely equal to the square of the separation between the masses and directly proportional to their product.

F = G\frac{m_{1} m_{2}}{r^{2}  }

to learn more about newton's law of gravitation go to - brainly.com/question/9373839

#SPJ4

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Answer:

The observed frequency by the pedestrian is 424 Hz.

Explanation:

Given;

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Based on Doppler effect, as the car the approaches the stationary observer, the observed frequency will be higher than the transmitted (source) frequency because of decrease in distance between the car and the observer.

The observed frequency is calculated as;

F_s = F_o [\frac{v}{v_s + v} ] \\\\

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F_s = F_o [\frac{v}{v_s + v} ] \\\\400 = F_o [\frac{340}{20 + 340} ] \\\\400 = F_o (0.9444) \\\\F_o = \frac{400}{0.9444} \\\\F_o = 423.55 \ Hz \\

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Therefore, the observed frequency by the pedestrian is 424 Hz.

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