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Minchanka [31]
3 years ago
12

The electric field direction is defined by the direction of the force felt by

Physics
1 answer:
RideAnS [48]3 years ago
7 0

Answer:

By a positive charge

Explanation:

The electric field is a vector consisting of a magnitude and a direction.

- The magnitude of the field depends on the configuration of the field: for example, for the electric field produced by a single point charge, it is

E=k\frac{q}{r^2}

where k is the Coulomb's constant, q is the magnitude of the charge, r is the distance from the charge.

- The direction of the field corresponds to the force that a positive charge would feel in that field. For example, the electric field produced by a single-point positive charge points away from the charge itself: this is because a positive test charge placed in this field would feel a repulsive force, so it  would move away from the source of the field. Vice-versa, the electric field produced by a single-point negative charge points towards the charge itself: this is because a positive test charge placed in this field would feel an attractive force, so it  would move towards the source of the field.

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Which of the following takes place during a double displacement reaction?
bogdanovich [222]
Double displacement: parts of compounds switch places to form two new compounds

FYI
decomposition: a complex substance breaks down into two or more simple substances

Single displacement: a single substance replaces another substance in a compound

<span>Synthesis: two simple substances combine to form a new complex substance</span>
4 0
3 years ago
Read 2 more answers
Instead of moving back and forth, a conical pendulum moves in a circle at constant speed as its string traces out a cone (see fi
tigry1 [53]

Answer:

a

The  radial acceleration is  a_c  = 0.9574 m/s^2

b

The horizontal Tension is  T_x  = 0.3294 i  \ N

The vertical Tension is  T_y  =3.3712 j   \ N

Explanation:

The diagram illustrating this is shown on the first uploaded

From the question we are told that

   The length of the string is  L =  10.7 \ cm  =  0.107 \ m

     The mass of the bob is  m = 0.344 \  kg

     The angle made  by the string is  \theta  =  5.58^o

The centripetal force acting on the bob is mathematically represented as

         F  =  \frac{mv^2}{r}

Now From the diagram we see that this force is equivalent to

     F  =  Tsin \theta where T is the tension on the rope  and v is the linear velocity  

     So

          Tsin \theta  =   \frac{mv^2}{r}

Now the downward normal force acting on the bob is  mathematically represented as

          Tcos \theta = mg

So

       \frac{Tsin \ttheta }{Tcos \theta }  =  \frac{\frac{mv^2}{r} }{mg}

=>    tan \theta  =  \frac{v^2}{rg}

=>   g tan \theta  = \frac{v^2}{r}

The centripetal acceleration which the same as the radial acceleration  of the bob is mathematically represented as

      a_c  =  \frac{v^2}{r}

=>  a_c  = gtan \theta

substituting values

     a_c  =  9.8  *  tan (5.58)

     a_c  = 0.9574 m/s^2

The horizontal component is mathematically represented as

     T_x  = Tsin \theta = ma_c

substituting value

   T_x  = 0.344 *  0.9574

    T_x  = 0.3294 \ N

The vertical component of  tension is  

    T_y  =  T \ cos \theta  = mg

substituting value

     T_ y  =  0.344 * 9.8

      T_ y  = 3.2712 \ N

The vector representation of the T in term is of the tension on the horizontal and the tension on the vertical is  

         

       T  = T_x i  + T_y  j

substituting value  

      T  = [(0.3294) i  + (3.3712)j ] \  N

         

3 0
3 years ago
A rocket ship is accelerating at 200 m/s2, its mas is 135,000,000 kg. What is the force generated by this acceleration?
Rina8888 [55]

Acceleration does NOT "generate" force.  Acceleration NEEDS force to make it happen.  Without force ... provided by something else ... acceleration can't happen.

The force NEEDED to accelerate a mass with a certain acceleration is

Force needed = (mass) times (acceleration)

For the rocket ship in the question,

Force = (135,000,000 kg) times (200 m/s²)

Force = (135,000,000 x 200) kg-m/s²

<em>Force = 27 Giga-Newtons  </em>(27,000,000,000 Newtons)


The gas-generator cycle F-1 rocket engine, developed in the US by Rocketdyne in the late 1950s, was used in the Saturn V rocket, the main launch vehicle of NASA's Apollo moon lander program .  Five F-1 engines were used in the first stage of each Saturn V.  

==> The thrust of each F-1 engine at full throttle is 7,770 kilo-Newtons.  

It would take <em>3,475 </em>of these F-1 rocket engines, running full-throttle, to provide the force calculated in the answer to this question.  If you didn't have 3,475 F-1 rocket engines, then you couldn't accelerate 135,000,000 kg at 200 m/s².

(And by the way ... the mass of each F-1 engine is 8,400 kg.  So 3,475 engines alone account for 22% of the mass you're trying to accelerate.  And don't even get me started about the mass of the FUEL you'd need to carry.)

5 0
3 years ago
What real-world examples show no work being done? Can you think of examples other than resisting the force of gravity?
GalinKa [24]

-- pushing on a brick wall

-- standing on your little brother's back so that he can't get up

-- taking a nap while on the job

-- squeezing anything that doesn't yield to your squeeze, such as a glass bottle or your girl friend

-- watching TV

-- solving math problems in your head

-- making pictures out of clouds in the sky

8 0
3 years ago
A 20.0-kg rock is dropped and hits the ground at a speed of 90.0 m/s. Calculate the rock’s gravitational potential energy before
KonstantinChe [14]
Answer:

<span>GPE=81000J or 81kJ</span>

Explanation

Potential Energy = mgh = 20 x 9.8 x ? 

<span>To find H use one of the equation of motion </span>

<span>= [(90)^2 - 0 ] / 2(9.8) </span>

<span>Potential Energy = mgh = 20 x 9.8 x 8100 /2(9.8) = 81000 J</span>

5 0
3 years ago
Read 2 more answers
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