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Licemer1 [7]
4 years ago
14

(PLEASE help me!! I will give 98 points [that's the most it would let me do] )

Physics
1 answer:
Marta_Voda [28]4 years ago
7 0

Answer:

the simple machines in this list are the saw, hammer, screwdriver, ruler, and the pulley system.

Explanation:

SAW:   place saw on wood then push and pull to shave away at the wood.

HAMMER:  aim for nail and hit really hard without hitting your hand.

SCREWDRIVER:   place screw bit in screw socket and twist.

RULER:   place against object and look at the mesurement on the numbers.

PULLEY: attach an object on one end of the pulley rope and pull on the other end to raise the end with the attached object.

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Two 2.0 kg bodies, A and B, collide. The velocities before the collision are ~vA = (15ˆi + 30ˆj) m/s and ~vB = (−10ˆi + 5.0ˆj) m
AleksandrR [38]

Answer:

Part a)

10\hat i + 15\hat j = \vec v

Part b)

\Delta K = 500 J

Explanation:

As we know that there is no external force on the system of two masses so here total momentum of the system will remains conserved

so we can say

m_1v_{1i} + m_2v_{2i} = m_1v_{1f} + m_2v_{2f}

(2kg)(15\hat i + 30 \hat j) + (2 kg)(-10\hat i  + 5\hat j) = 2kg(-5\hat i + 20\hat j) + 2\vec v

5\hat i + 35\hat j = (-5\hat i + 20\hat j) +\vec v

10\hat i + 15\hat j = \vec v

Part b)

magnitude of the initial speed of A = \sqrt{15^2 + 30^2} = 33.54 m/s

magnitude of the initial speed of B = \sqrt{10^2 + 5^2} = 11.18 m/s

magnitude of final speed of A = \sqrt{5^2 + 20^2} = 20.61 m/s

magnitude of final speed of B = \sqrt{10^2 + 15^2} = 18.03 m/s

Now change in total kinetic energy is given as

\Delta K = (\frac{1}{2}m_1v_{1i}^2 + \frac{1}{2}m_2v_{2i}^2) - (\frac{1}{2}m_1v_{1f}^2 + \frac{1}{2}m_2v_{2f}^2)

\Delta K = (\frac{1}{2}2(33.54)^2 + \frac{1}{2}2(11.18)^2) - (\frac{1}{2}2(20.61)^2 + \frac{1}{2}2(18.03)^2)

\Delta K = 500 J

6 0
4 years ago
A 580-mm long tungsten wire, with a 0.046-mm-diameter circular cross section, is wrapped around in the shape of a coil and used
Blizzard [7]

Answer:

a,b)   #_ {electron} = 1.64 10¹⁹ electrons, c)  R = 19.54  Ω, d)   V = 10.3 V

Explanation:

a and b) The current is defined as the number of electrons that pass per unit of time

let's look for the load

            Q = I t

            Q = 0.526  5

            Q = 2.63 C

Let's use a direct rule of three proportions. If an electron has a charge of 1.6 10⁻¹⁹ C, how many electrons does 2.63 C have?

           #_ {electron} = 2.63 C (1 electron / 1.6 10⁻¹⁹)

           #_ {electron} = 1.64 10¹⁹ electrons

         

c) the resistance of a wire is given by

          R = ρ l / A

           

where the resistivity of tungsten is 5.6 10⁻⁸ Ω

the area of ​​the wire is

           A = π r2 = π d²/4

         

we substitute

            R = \rho \ l \ \frac{4}{\pi  d^2}

let's calculate

           R = 5.6 10⁻⁸  0.580 \frac{4}{ \pi  (0.046 \ 10^{-3})^2 }

           R = 19.54  Ω

d) let's use ohm's law

           V = i R

            V = 0.526 19.54

            V = 10.3 V

7 0
3 years ago
What is one action a person can take to help ensure ability to participate in physical activity thoughout life
ivanzaharov [21]

Answer:

They can join a gym or a class to help keep themselves motivated to exercise.

Explanation:

8 0
2 years ago
A scientist kept 1,000 grams of a radioactive material in a container. After 66 days, he observed that 125 grams of the radioact
bixtya [17]
The sample appears to have gone through 3 half-lives
1st half life: 1000 to 500 g
2nd half life: 500 to 250 g
3rd half life: 250 to 125 g
The duration of a half-life, therefore, can be inferred to be 66 ÷ (3) = 22 days. 

After a 4th half life, there will be 125÷2= 62.5 g. 
At this point, an additional 22 days will have passed, for a total of 88 days.
Answer is C. 

8 0
4 years ago
A rabbit is moving in the positive x-direction at 1.10 m/s when it spots a predator and accelerates to a velocity of 10.9 m/s al
anzhelika [568]

Answer:

aₓ = 0 ,       ay = -6.8125 m / s²

Explanation:

This is an exercise that we can solve with kinematics equations.

Initially the rabbit moves on the x axis with a speed of 1.10 m / s and after seeing the predator acceleration on the y axis, therefore its speed on the x axis remains constant.

x axis

          vₓ = v₀ₓ = 1.10 m / s

          aₓ = 0

y axis

initially it has no speed, so v₀_y = 0 and when I see the predator it accelerates, until it reaches the speed of 10.6 m / s in a time of t = 1.60 s. let's calculate the acceleration

         v_{y}= v_{oy} -ay t

          ay = (v_{oy} -v_{y}) / t

          ay = (0 -10.9) / 1.6

          ay = -6.8125 m / s²

the sign indicates that the acceleration goes in the negative direction of the y axis

8 0
3 years ago
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