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dezoksy [38]
2 years ago
9

What potential difference is needed to give a helium nucleus (q=2e) 85.0 kev of kinetic energy?

Physics
1 answer:
Vilka [71]2 years ago
6 0
The kinetic energy K given to the helium nucleus is equal to its potential energy, which is 
E=q \Delta V
where q=2e is the charge of the helium nucleus, and \Delta V is the potential difference applied to it.
Since we know the kinetic energy, we have
E=K=85~keV=q \Delta V
and from this we can find the potential difference:
\Delta V =  \frac{K}{q}= \frac{85~keV}{2e}=42.5~kV

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m =  the mass of the object
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Explanation:

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Read 2 more answers
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