Answer:
2Fe(s) + 3O2(g) --------> 2FeO3(s)
Explanation:
According to the question, a battery was used to light the steel wool by bringing the terminals very close together. When the battery came into contact with the steel wool, current was sent out through the thin wire. This caused the iron to heat up quite well.
Iron reacts with oxygen under these conditions as follows;
2Fe(s) + 3O2(g) --------> 2FeO3(s)
This is the chemical reaction that occurs when the steel wool is set on fire.
Answer:
1422mg of acetaminophen
Explanation:
The maximum dose of acetaminophen is 15.0 mg of acetaminophen per kg of person.
To know the maximum single dosage of the person we need to convert the 209lb to kg (Using 1kg = 2.2046lb):
209lb * (1kg / 2.2046lb) = 94.8
The person weighs 94.8kg and the maximum single dosage for the person is:
94.8kg * (15.0mg acetaminophen / kg) =
1422mg of acetaminophen
1.
V = 200 mL (volume)
c = 3 M = 3 mol/L (concentration)
First we convert mL to L:
200 mL = 0.2 L
Then we calculate the moles using the formula: n = V × c = 0.2 L × 3 mol = 0.6 mol
Finally, we just use the molar mass of CaF2 to calculate the actual mass:
molar mass = 78 g/mol
The formula is: m = n × mm (mass = moles × molar mass)
m = 0.6 mol × 78 g/mol = 46.8 g
2.
For this question the steps are exactly like the first question.
V = 50mL = 0.05 L
c = 12 M = 12 mol/L
n = V × c = 0.05 L × 12 mol/L = 0.6 mol
molar mass (HCl) = 36.5 g/mol
m = n × mm = 0.6 mol × 36.5 g/mol = 21.9 g.
3.
The steps for this question are the opposite way.
m(K2CO3) = 250 g
molar mass = 138 g/mol
n = m ÷ mm = 1.81 mol
c = 2 mol/L
V = n ÷ c = 1.81 mol ÷ 2 mol/L = 0.905 L = 905 mL
Answer:
A compound by definition contains at least 2 different kinds of atoms. A Hydrogen molecule contains only one kind of atom, 2 hydrogen atoms
Answer is: 588.15 <span>grams of ethanol.
</span>Chemical reaction: C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂.
m(C₆H₁₂O₆) = 1150 g.
n(C₆H₁₂O₆) = m(C₆H₁₂O₆) ÷ M(C₆H₁₂O₆).
n(C₆H₁₂O₆) = 1150 g ÷ 180.16 g/mol.
n(C₆H₁₂O₆) = 6.38 mol.
From chemical reaction: n(C₆H₁₂O₆) : n(C₂H₅OH) = 1 : 2.
n(C₂H₅OH) = 12.76 mol.
m(C₂H₅OH) = 12.76 mol · 46.07 g/mol.
m(C₂H₅OH) = 588.15 g.
