There are 12 such shapes. One can start with two squares, adding squares around the edge and rejecting shapes that have been previously seen. Repeating until you have 5 squares results in 12 distinct shapes.
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2 shapes are possible with 3 squares: L, I
5 shapes are possible with 4 squares: L, I, N, T, O
Answer:
Step-by-step explanation:
First, distribute the 2 to the 3z and -6 within the parenthesis.
You know have 6z -12/5 + 6 = 10
Subtract 6 from both sides of the equation
6z -12/5 = 4
Multiply 5 on both sides of the equation
6z -12 = 20
Add 12 to both sides of the equation
6z = 32
Divide by 6 on both sides of the equation
z = 32/6
Simplify
z = 16/3
I hope that this helps! :)
Should be D. Let me know if you need more of an explanation.
Since you're only asked the ordered pair of D'', it's much easier just to plot and reflect point D twice than to do that for all four points!
Remember that reflecting points is like putting a mirror at the line of reflection or flipping that point over at that line. The reflected point should be the same distance from the line of reflection as the original point.
1) Reflect D over the x-axis to get D'.
D is at (4,1). Draw a line that is perpendicular to the line of reflection and goes through D. D is as far from the line of reflection as D' should be on its other side (both are on that perpendicular line). Since D is 1 unit above the x-axis, that means D' is 1 unit below at (4, -1). See picture 1.
2) Reflect D' over <span>y=x+1 to get D''.
D' is at (4, -1). Draw </span>y=x+1 and the line perpendicular to it going through D''. D'' is the same distance from the line of reflection on the other side. See picture 2. D'' is at (-2, 5).
Answer: D'' is at (-2, 5)
