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DedPeter [7]
4 years ago
11

Which is a chemical property of soda ash? A.It's a highly basic substance. B.It's a white crystalline powder. It can dissolve in

water. C.It can be separated from water by distillation. D.NextReset
Chemistry
2 answers:
masha68 [24]4 years ago
8 0
I think it's A because I already had that question
LenaWriter [7]4 years ago
5 0
A) its a highly basic substance
You might be interested in
Select the correct answer.
muminat

Answer:- B. 4.65 g.

Solution:- The given balanced equation is:

2AgNO_3(aq)+Na_2S(aq)\rightarrow Ag_2S(s)+2NaNO_3(aq)

It asks to calculate the mass of silver sulfide formed by when 0.0150 liters of 2.50 M of silver nitrate are used.

Moles of silver nitrate are calculated on multiplying it's liters by its molarity and then on multiplying by mol ratio, the moles of silver sulfide are calculated. These moles are multiplied by the molar mass to convert to the grams.

Molar mass of Ag_2S = 2(107.87)+32.06  = 247.8 g per mol

The dimensional set up for the complete problem is:

0.0150L(\frac{2.50molAgNO_3}{1L})(\frac{1molAg_2S}{2molAgNO_3})(\frac{247.8gAg_2S}{1molAg_2S})

= 4.65gAg_2S

So, the correct choice is B. 4.65 g.


7 0
3 years ago
What is the dewpoint when the air temperature is 26c and the relative humidity is 77%?
Zielflug [23.3K]
The dew point would be about 22 . (this is C )  
7 0
3 years ago
Read 2 more answers
Consider the reaction at 25 °C. H2O(l) ↔ H2O(g) ΔG° = 8.6 kJ/mol Calculate the pressure of water at 25 °C (Hint: Get K eq)
tangare [24]

Answer:

\boxed{\text{23.4 mmHg}}

Explanation:

H₂O(ℓ) ⟶ H₂O(g)

K_{\text{p}} = p_{\text{H2O}}

\text{The relationship between $\Delta G^{\circ}$ and $K_{\text{ p}}$ is}\\\Delta G^{\circ} = -RT \ln K_{\text{p}}

Data:  

T = 25 °C

ΔG° = 8.6 kJ·mol⁻¹

Calculations:

T = (25 + 273.15) K = 298.15 K

\begin{array}{rcl}8600 & = & -8.314 \times 298.15 \ln K \\8600 & = & -2478.8 \ln K\\-3.47 & = & \ln K\\K&=&e^{-3.47}\\& = & 0.0311\end{array}

Standard pressure is 1 bar.

p_{\text{H2O}} = \text{0.0311 bar} \times \dfrac{\text{750.1 mmHg}}{\text{1 bar}} = \textbf{23.4 mmHg}\\\\\text{The vapour pressure of water at $25 ^{\circ}\text{C}$ is $\boxed{\textbf{23.4 mmHg}}$}

4 0
3 years ago
This law relates a planet's orbital period and its average distance to the Sun.
Tanya [424]

Answer:

These are Kepler's Laws of Planetary Motion

Explanation:

3 0
3 years ago
How does oxygen concentration affect the fish that live in a pond
Maurinko [17]

Explanation: Oxygen plays a very vital role in the life of aquatic animals. The dissolved oxygen in the water helps them to breathe under water.

Optimum level of oxygen for deep living animals like oysters, bottom feeders, crabs is around (1-6 mg/L), while the animals living on the upper side like fishes require a higher amount of around (4-6 mg/L).

If the oxygen concentration in the pond is not optimum, there will no aquatic life and hence, the ecosystem will be affected.

Hence, oxygen concentration affects the fishes that live in the pond to a higher extent.

3 0
3 years ago
Read 2 more answers
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