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3 years ago

What is the momentum of a 5 kg object that has a velocity of 1.2 m/s? 3.8 kg • m/s 4.2 kg • m/s 6.0 kg • m/s 6.2 kg • m/s

Physics

2 answers:

Gnesinka [82]3 years ago

4 0

Answer:

Your answer will be 6.0kg•m/s

Explanation:

In the given question all the required details d given. Using these information's a person can easily find the momentum of the object. In the question it is already given that the mass of the object is 5 kg and the velocity at which it is traveling is 1.2 m/s.We know the equation of finding momentum asMomentum = mass * velocity = 5 * 1.2 = 6So the momentum of the object is 6 Newton.

Julli [10]3 years ago

3 0

Answer:

Momentum of an object, p = 6 kg-m/s

Explanation:

It is given that,

Mass of an object, m = 5 kg

Velocity of that object, v = 1.2 m/s

We need to find the momentum of an object. It is equal to the product of mass and its velocity. Mathematically, it is given by :

p = m v

$p=5\ kg\times 1.2\ m/s$

p = 6 kg-m/s

So, the momentum of an object is 6 kg-m/s. Hence, this is the required solution.

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Answer:

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Ivahew [28]

Answer:

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n 38 g rifle bullet traveling at 410 m/s buries itself in a 4.2 kg pendulum hanging on a 2.8 m long string, which makes the pend

Kitty [74]

Answer:

68cm

Explanation:

You can solve this problem by using the momentum conservation and energy conservation. By using the conservation of the momentum you get

$p_f=p_i\\mv_1+Mv_2=(m+M)v$

m: mass of the bullet

M: mass of the pendulum

v1: velocity of the bullet = 410m/s

v2: velocity of the pendulum =0m/s

v: velocity of both bullet ad pendulum joint

By replacing you can find v:

$(0.038kg)(410m/s)+0=(0.038kg+4.2kg)v\\\\v=3.67\frac{m}{s}$

this value of v is used as the velocity of the total kinetic energy of the block of pendulum and bullet. This energy equals the potential energy for the maximum height reached by the block:

$E_{fp}=E_{ki}\\\\(m+M)gh=\frac{1}{2}mv^2$