A) 4.7 cm
The formula for the angular spread of the nth-maximum from the central bright fringe for a diffraction from two slits is

where
n is the order of the maximum
is the wavelength
is the distance between the slits
In this problem,
n = 5


So we find

And given the distance of the screen from the slits,

The distance of the 5th bright fringe from the central bright fringe will be given by

B) 8.1 cm
The formula to find the nth-minimum (dark fringe) in a diffraction pattern from double slit is a bit differente from the previous one:

To find the angle corresponding to the 8th dark fringe, we substitute n=8:

And the distance of the 8th dark fringe from the central bright fringe will be given by

Answer:
+ 3.0 m
Explanation:
displacement is shortest distance from fixed point O in particular direction . in diagram shortest distance at end from O is 3 m and it is right of O so +. HENCE +3.0m
Answer:
Temperature, T = 3.62 kelvin
Explanation:
It is given that,
Total number of gas molecules, 
Her body is converting chemical energy into thermal energy at a rate of 125 W, P = 125 W
Time taken, t = 6 min = 360 s
Energy of a gas molecules is given by :

, k is Boltzmann constant


T = 3.62 K
So, the temperature increases by 3.62 kelvin. Hence, this is the required solution.
Answer:
2) c) give-way vessel
3) a) With one short blast
Explanation:
2) A vessel that is required to take early substantial action to ensure avoiding collision called Give way vessel
In overtaking, the vessel intending to overtake is the Give-Way Vessel the vessel that is going to be overtaken is the Stand-On Vessel
Therefore, the correct option is c) give-way vessel
3) When vessels use sound signals in a meeting head on situation both vessel are Give-Way vessels and both vessel pass the each other by turning to the starboard side therefore they intend to pass each other on their port side requiring one short blast
Therefore, the correct option is a) With one short blast.
We have that valence electrons poses the three characteristics stated, as
Group 14 (carbon group) are identified by 4 valence electrons.
Valence electrons of atoms are used to form bonds.
Group 14 (carbon group) are identified by 4 valence electrons.
Option A,B,C
<h3>
Properties of Valence electrons</h3>
All elements in the same group or family have the same number of valence electrons: Yes, this is true as Group 14 (carbon group) are identified by 4 valence electrons.
Valence electrons are the only subatomic particles involved in forming bonds: Yes, Valence electrons of atoms are used to form bonds.
Carbon has 4 valence electrons because it is found in group 14:
True, Group 14 (carbon group) are identified by 4 valence electrons.
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