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oee [108]
3 years ago
8

Describe the arguments supporting the idea that quasars are at the distances indicated by their redshifts.

Physics
1 answer:
Fynjy0 [20]3 years ago
6 0

Answer:

The redshifts of the underlying galaxies match the redshifts of the quasars in their center and thus quasars are at distances indicated by their redshifts.

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Why does it take the water in a swimming pool some time to heat up during a hot day?
BartSMP [9]
Because the top layer of a pool will be warmer than the bottom layer, that why filtration is important to cycle the water evenly.
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4 years ago
With what force will a car hit a tree if the car has a mass of 3,000 kg and it is accelerating at a rate of 2m/s2
Arisa [49]
<span>F=ma = 3000x2m/sec^2 =6000 newtons. </span>
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4 years ago
A skateboarder jumps horizontally off the top of a staircase at a speed of 14.5 – and lands at bottom of the
Marrrta [24]

Question:

A skateboarder jumps horizontally off the top of a staircase at a speed of 14.5 and lands at bottom of the stairs. The staircase has a horizontal length of 8.00 m. We can ignore air resistance. What is the skater's vertical displacement during the jump?

Answer:

y = 1.48 m

Explanation:

Projectile motion is a two dimensional motion experienced by an object or particle that is subjected near the Earth's surface and moves along a curved path under the influence of gravity only. The path followed by projectile motion is called projectile path.

As the skateboarder followed the projectile path, and we know that in projectile motion the horizontal component of the velocity remain constant throughout his motion. So there is no acceleration along horizontal path.

Also Skateboard jumps horizontally, So initial velocity has only horizontal component.

Horizontal component of initial velocity = v_{i_{x}} = 14.5 m/s

Horizontal displacement = x = 8.00 m

Vertical displacement = y = ?

Using the following formula

x = v_{i_{x}}t

8 = (14.5)(t)

t = 0.55 s

As skateboarder jumps horizontally, So there is no vertical component of velocity.

According to 2nd equation of motion

y = v_{i_{y}}t + \frac{1}{2}gt^{2}

As v_{i_{y}} = 0

So

y = 0.5gt²

y = 0.5*9.8*(0.55)²

y = 1.48 m

8 0
3 years ago
Read 2 more answers
Electromagnetic radiation travels as
Dima020 [189]
2 I hope it help sorry if it is wrong
7 0
3 years ago
When you drink cold water, your body must expend metabolic energy in order to maintain normal body temperature (37° C) by warmin
Andre45 [30]

Answer:

V=12.1622\ L

Explanation:

Given:

  • Initial temperature of water, T_i=0^{\circ}C
  • final temperature of water, T_f=37^{\circ}C
  • energy spent in one hour of walk, Q=450\ kcal=450\times4186=1883700\ J
  • volumetric capacity of stomach, V=1\ L

<em>Now, let </em><em>m </em><em>be the mass of water at zero degree Celsius to be drank to spend 450 kilo-calories of energy.</em>

We know:

Q=m.c.\Delta T .....................................(1)

where:

m = mass of water

Q = heat energy

\Delta T= temperature difference

c=4186\ J.kg^{-1}.K^{-1} = specific heat capacity of water

<u>Putting values in the eq. (1):</u>

1883700=m\times 4186\times 37

m=12.1622\ kg

Since water has a density of 1 kilogram per liter, therefore the volume of water will be:

V=12.1622\ L

8 0
3 years ago
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