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3 years ago

What is ohm law form?

2 answers:

7 0

Ohm's Law is the mathematical relationship among electric current, resistance, and voltage. The principle is named after the German scientist Georg Simon Ohm. In direct-current (DC) circuits, Ohm's Law is simple and linear. Suppose a resistance having a value of R ohm s carries a current of I ampere s.

Lady_Fox [76]3 years ago

6 0

Answer:

$V=RI$

Explanation:

Ohm's law states the relationship between voltage, resistance and current in an electrical circuit containing passive elements only:

$V=RI$

where

V is the voltage supplied by the battery

R is the resistance of the circuit

I is the current

From the equation, we see that the voltage, V, is directly proportional to the current in the circuit, I.

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What injuries could occur due to incorrect movement and handling of equipment with any sport or activity? (Select ALL that apply

NeTakaya

Sprains/Strains, tears to muscles, tendons ligaments, not hypothermia bc thats when you get really cold and not dehydrated

4 0

3 years ago

Light of wavelength 623.0 nm is incident on a narrow slit. The diffraction pattern is viewed on a screen 76.5 cm from the slit.

Dvinal [7]

Answer:

Explanation:

wave length of light λ = 623 x 10⁻⁹ m .

Distance of screen D = 76.5 x 10⁻² m

width of slit = d

Distance on the screen between the second order minimum and the central maximum = 2 λ D / d

1.11 x 10⁻² = (2 x 623 x 10⁻⁹ x 76.5 x 10⁻² )/ d

d = ( 2 x 623 x 10⁻⁹ x 76.5 x 10⁻²) / 1.11 x 10⁻²

= 85872.97 x 10⁻⁹

= 85.87297 x 10⁻⁶

= 85.87 μm

width a of the slit is = 85.87 μm

6 0

3 years ago

What’s the answer ?????

Mice21 [21]

Answer:

<h2>Refer the attachment for answer and explanation please</h2>

Explanation:

This might surely help you ☺️❤️

7 0

3 years ago

HELP ME PLEASE If an object is placed under a force of 20 N, it accelerates at a rate of 5 m/s^2. If the force is increased to 5

lara [203]

Answer:

Explanation:

3 0

3 years ago

Read 2 more answers

A 500 kg sack of coal falls vertically onto a 2000 kg railroad flatcar which was initially moving horizontally at 3 m/s. no exte

Zinaida [17]

Since there are no external forces, including friction, act on the flatcar. after the sack rests on the flatcar, we would assume that momentum is conserved. This means that

total momentum of car before collision = total momentum of car after collision.

Recall,

momentum = mass x velocity

From the information given,

mass of car before collision = 2000

velocity of car before collision = 3

Thus,

total momentum of car before collision = 2000 x 3 = 6000

Also,

mass of sack = 500

mass of car and sack after collision = 500 + 2000 = 2500

velocity after collision = v

momentum after collision = 2500 x v = 2500v

Since momentum is conserved, then

6000 = 2500v

v = 6000/2500

v = 2.4

the speed of the flatcar is 2.4 m/s

6 0

11 months ago