Q1. The answer is 8.788 m/s
V2 = V1 + at
V1 - the initial velocity
V2 - the final velocity
a - the acceleration
t - the time
We have:
V1 = 4.7 m/s
a = 0.73 m/s²
t = 5.6 s
V2 = ?
V2 = 4.7 + 0.73 * 5.6
V2 = 4.7 + 4.088
V2 = 8.788 m/s
Q2. The answer is 9.22 s
V2 = V1 + at
V1 - the initial velocity
V2 - the final velocity
a - the acceleration
t - the time
We have:
V2 = 0 (because it reaches a complete stop)
V1 = 4.7 m/s
a = -0.51 m/s²
t = ?
0 = 4.7 + (-0.51)*t
0 = 4.7 - 0.51t
0.51t = 4.7
t = 4.7 / 0.51
t = 9.22 s
Answer: A student walks 50 meters east, 40 meters north, 35 meters east, and then 20 m south. Then the magnitude and direction of the student's total displacement will be 87.32 m along the direction of AD or in east-south direction.
Explanation: To find the correct answer, we need to know about the Displacement of a body in motion.
<h3>What is displacement of a body in motion?</h3>
- The displacement is the shortest distance between initial and final positions of a body.
- It's a vector quantity, and can positive, negative, or zero.
- The magnitude of displacement is less than or equal to the distance travelled.
<h3>How to solve the problem?</h3>
- At first, we can draw a diagram showing the motion of the body.
- From the diagram, the displacement of the body will be equal to the distance between point A and D.
- To solve this, we can use Pythagoras theorem.

Thus, from the above calculations, we can conclude that, the displacement of the body will be equal to 87.32 m along the direction of AD or in east-south direction.
Learn more about the Displacement here:
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Answer:
Maximum altitude above the ground = 1,540,224 m = 1540.2 km
Explanation:
Using the equations of motion
u = initial velocity of the projectile = 5.5 km/s = 5500 m/s
v = final velocity of the projectile at maximum height reached = 0 m/s
g = acceleration due to gravity = (GM/R²) (from the gravitational law)
g = (6.674 × 10⁻¹¹ × 5.97 × 10²⁴)/(6370000²)
g = -9.82 m/s² (minus because of the direction in which it is directed)
y = vertical distance covered by the projectile = ?
v² = u² + 2gy
0² = 5500² + 2(-9.82)(y)
19.64y = 5500²
y = 1,540,224 m = 1540.2 km
Hope this Helps!!!
Answer:
0
Explanation:
The overall charge on this atom is 0.
To find the charge on an atom;
charge = number of protons - number of electrons.
Note:
- Protons are the positively charged particles in an atom
- Electrons are the negatively charged particles in an atom
- Neutrons carries no charges on them.
Since the atom is made up of equal number of protons and electrons, the charge on it is 0.
If the number of electrons is more, the atom will be negatively charge but if the number of protons is more, it will be positively charged.
Answer:3,600 Newtons
Explanation:
The net force acting on the car is
3×10^3squared
Newtons.
Force is defined as the product of the mass of the body and its aaceleration,⇒F=ma
Substituting the above given values we get,F=(1500kg) (2.0m /s^2 squared)=3000 N=3×10^3 squared N.
N=newtons