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astra-53 [7]
3 years ago
5

How much force is required to accelerate a 2 kg mass at 3 m/s2

Physics
2 answers:
nadya68 [22]3 years ago
7 0
Force = mass x acceleration
= 2 x 3 = 6 Newtons
Lesechka [4]3 years ago
4 0
F = ma
F = 2 *3
F = 6 N
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Calculate the drop voltage for a battery of internal resistance 2 ohm and emf of 24 volt
Ivenika [448]

Answer:

<em>The drop voltage is 0.3 V</em>

Explanation:

Electromotive Force EMF

When connecting a battery of internal resistance Ri and EMF ε to an external resistance Re, the current through the circuit is:

\displaystyle i=\frac{\varepsilon }{R_e+R_i}

The battery has an internal resistance of Ro=2 Ω, ε=24 V and is connected to an external resistance of Re=158 Ω. Thus, the current is:

\displaystyle i=\frac{24 }{158+2}

\displaystyle i=\frac{24 }{160}

i = 0.15 A

The drop voltage is the voltage of the internal resistance:

V_i = i.R_i

V_i = 0.15*2

\boxed{V_i = 0.3\ V}

The drop voltage is 0.3 V

3 0
3 years ago
When performing an.experiment similar to Millikan's oil drop, a student measured the following load magnitudes: 3.26x10 ^-19 C 5
torisob [31]

Answer:

Explanation:

We put the charges in the ascending order as follows

1.53 P

3.26 P

4.66 P

5.09 P

6.39 P

where P is equal to 10⁻¹⁹

we round off given charges as follows

1.53 P → 1.6 P

3.26 P → 3.2 P

4.66 P → 4.8 P

5.09 P → 4.8 P

6.39 P → 6.4 P

We see that 2 nd to 4 th charges are integral multiples of first charge . That means these charges are supposed to be made of combination of first charge . So first charge appears to be minimum possible charge .

Hence this charge may exist on single electron.

8 0
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Me finding out bananas are curved because they grow towards the sun what do you think about this ?
Goryan [66]
Answer:

Bananas go through a unique process known as negative geotropism. Instead of continuing to grow towards the ground, they start to turn towards the sun. The fruit grows against gravity, giving the banana its familiar curved shape.
7 0
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SP: Calculate the moment
ipn [44]

Answer:

Moment of the force is 20 N-m.

Explanation:

Given:

Force exerted by the person is, F=80\ N

Distance of application of force from the point about which moment is needed is, d=25\ cm=\frac{25}{100}\ m=0.25\ m

Now, we know that, moment of a force 'F' about a point at a perpendicular distance of 'd' from the same point is given as the product of the force and the perpendicular distance.

Therefore, the moment of the force about the end of the claw hammer is given as:

M=F\times d\\\\M=(80\ N)(0.25\ m)\\\\M=20\textrm{ N-m}

Hence, the moment of the force exerted by the person about the end of the claw hammer is 20 N-m.

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3 years ago
A pitcher throws a baseball at 45 m/s. The baseball has a mass of 400 grams. Disregarding air resistance, the baseball's momentu
enyata [817]
So it would be 8.90 m/s kg*m/s
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