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Olegator [25]
3 years ago
7

KOH (aq) + HC2H3O2 (aq) ?

Chemistry
1 answer:
Radda [10]3 years ago
3 0
KOH  <span> + HC</span>₂<span>H</span>₃<span>O</span>₂<span> = H</span>₂<span>O + KC</span>₂<span>H</span>₃<span>O</span><span>₂

hope this helps!</span>
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Name 2 separate problems that occur when a sample for infrared analysis is contaminated with water.
Andreyy89

Explanation:

  • The water molecules gets trapped in the crystal structure to be analysed and will give a peak in the spectra at about 3500 /cm , and there by hindering with the IR spectra of the sample to be analysed .
  • The second problem with the contamination of the sample with water is , that water makes the potassium bromide disc opaque which will decrease the absorption of the IR by the sample .
7 0
3 years ago
Elements - made up of<br> Ex:
astra-53 [7]
All elements are made up of atoms. ➢ Atoms are made up of protons, neutrons, and electrons. Two different kinds of atoms can combine to form a compound. A molecule is a combination of atoms that cannot be broken apart while still retaining the same properties as the larger substance that it is a part of.
7 0
3 years ago
What volume in liters of carbon monoxide will be required to produce 18.9 L of nitrogen in the reaction below
mina [271]

Answer:

37.8 L OF CARBON MONOXIDE IS REQUIRED TO PRODUCE 18.9 L OF NITROGEN.

Explanation:

Equation for the reaction:

2 CO + 2 NO ------> N2 + 2 CO2

2 moles of carbon monoxide reacts with 2 moles of NO to form 1 mole of nitrogen

At standard temperature and pressure, 1 mole of a gas contains 22.4 dm3 volume.

So therefore, we can say:

2 * 22.4 L of CO produces  22.4 L of N2

44.8 L of CO produces 22.4 L of N2

Since, 18.9 L of Nitrogen is produced, the volume of CO needed is:

44.8 L of CO = 22.4 L of N

x L = 18.9 L

x L = 18.9 * 44.8 / 22.4

x L = 18.9 * 2

x = 37.8 L

The volume of Carbon monoxide required to produce 18.9 L of N2 is 37.8 L

8 0
3 years ago
An arctic weather balloon is filled with 27.8 L of helium gas inside a prep shed. The temperature inside the shed is . The ballo
Liula [17]

The question is incomplete, here is a complete question.

An arctic weather balloon is filled with 27.8 L of helium gas inside a prep shed. The temperature inside the shed is 13 ⁰C. The balloon is then taken outside, where the temperature is -9 ⁰C. Calculate the new volume of the balloon. You may assume the pressure on the balloon stays constant at exactly 1 atm. Be sure your answer has the correct number of significant digits.

Answer : The new volume of the balloon is 25.7 L

Explanation :

Charles's Law : It is defined as the volume of the gas is directly proportional to the temperature of the gas at constant pressure and number of moles.

V\propto T

or,

\frac{V_1}{T_1}=\frac{V_2}{T_2}

where,

V_1 = initial volume of gas = 27.8 L

V_2 = final volume of gas = ?

T_1 = initial temperature of gas = 13^oC=273+13=286K

T_2 = final temperature of gas = -9^oC=273+(-9)=264K

Now put all the given values in the above equation, we get:

\frac{27.8L}{286K}=\frac{V_2}{264K}

V_2=25.7L

Therefore, the new volume of the balloon is 25.7 L

3 0
2 years ago
The elements potassium (K), Calcium (Ca), and Krypton(Kr) are all part of the same __________ on the periodic table. A) Diagonal
Pavel [41]
The answer is C, I believe.
6 0
2 years ago
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