All categories

4 years ago

Jim is playing with a 1-meter-long pendulum that is hooked

Physics

2 answers:

iogann1982 [59]4 years ago

8 0

Answer:

C. At the highest position of the bob, the KE is equal to zero.

Explanation:

When pendulum bob is at highest position then the bob is released from rest position

So at that instant of time the pendulum bob is at rest position so we can say that

initial total energy = kinetic energy + potential energy

As we have taken the ground position as reference so at the ground potential energy is zero

Since pendulum will never touch the ground position so here potential energy of pendulum never equal to zero

Now when pendulum is released its potential energy will convert into kinetic energy

So here correct answer will be

C. At the highest position of the bob, the KE is equal to zero.

Inessa [10]4 years ago

5 0

The answer would be C. <span />

You might be interested in

A block of mass m is placed on a smooth wedge of inclination θ . The whole system is accelerated horizontally so that the block

Helen [10]

Answer: mg/Cosθ

Explanation:

Taking horizontal acceleration of wedge as 'a'

FCosΘ = FsinΘ

F = mass(m) × acceleration(a) = ma

For horizontal resolution g = 0

Therefore,

Horizontal = Vertical

maCosΘ = mgSinΘ

aCosΘ = gSinΘ

a = gSinΘ/CosΘ

Recall from trigonometry :

SinΘ/Cosθ = tanΘ

Therefore,

a = gtanΘ

Normal force acing on the wedge:

mgCosΘ + maSinΘ - - - - (y)

Substitute a = gtanΘ into (y)

mgCosΘ + mgtanΘsinΘ

tanΘ = sinΘ/cosΘ

mgCosΘ + mgsinΘ/cosΘsinΘ

mgCosΘ + mgsin^2Θ/cosΘ

Factorizing

mg(Cosθ + sin^2Θ/cosΘ)

Taking the L. C. M

mg[(Cos^2θ + sin^2Θ) /Cosθ]

Recall: Cos^2θ + sin^2Θ = 1

mg[ 1 /Cosθ]

mg/Cosθ

6 0

3 years ago

Which statement best describes the positions of the two elements in the periodic table?

vagabundo [1.1K]

The two elements are in the same period, with Element R the first element in the period and Element Q the last element.

4 0

3 years ago

A uniform rod is 2. 0 m long and has mass 15 kg. What is most nearly the rod's mass moment of inertia?

trapecia [35]

The rod's mass moment of inertia is 5kgm².

<h3>Moment of Inertia:</h3>

The "sum of the product of mass" of each particle with the "square of its distance from the axis of rotation" is the formula for the moment of inertia.

The Parallel axis Theorem can be used to compute the moment of inertia about the end of the rod directly or to derive it from the center of mass expression. I = kg m². We can use the equation for I of a cylinder around its end if the thickness is not insignificant.

If we look at the rod we can assume that it is uniform. Therefore the linear density will remain constant and we have;

or = M / L = dm / dl

dm = (M / L) dl

$I = \int\limits^M_0 {r^2} \, dm$

$I = \int\limits^\frac{L}{2} _\frac{-L}{2} {I^2 (M/L)} \, dl$

Here the variable of the integration is the length (dl). The limits have changed from M to the required fraction of L.

$I = \int\limits^\frac{L}{2} _\frac{-L}{2} {I^2 (M/L)} \, dl$

$I = \frac{M}3L}[(\frac{L^3}{2^3} - \frac{-L^3}{2^3} )]\\\\I = \frac{1}{12}ML^2$

Mass of the rod = 15 kg

Length of the rod = 2.0 m

Moment of Inertia, I = $\frac{1}{12}15 (2)^2$

= 5 kgm²

Therefore, the moment of inertia is 5kgm².

Learn more about moment of inertia here:

brainly.com/question/14119750

#SPJ4

4 0

2 years ago

The magnetic force of a magnet is stronger at its poles than in the middle.<br> true or false

earnstyle [38]

The magnetic field of a bar magnet is strongest at either pole of the magnet. It is equally strong at the north pole when compared with the south pole. The force is weaker in the middle of the magnet and halfway between the pole and the center.

8 0

3 years ago

Read 2 more answers

Which list of factors best supports the concept that they are "just right" for the planet earth to support life?

Ivanshal [37]

Temperature, gravity, atmosphere and water

8 0

3 years ago

Read 2 more answers