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alina1380 [7]
3 years ago
6

What do both plants and animal cells break down for energy?

Chemistry
2 answers:
Naya [18.7K]3 years ago
3 0

Answer:

both plant and animal cells must break down food molecules to get energy from them

jenyasd209 [6]3 years ago
3 0
Plants and animal cells break down stores glucose & oxygen for energy.
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How many grams of sulfuric acid is needed to neutralize 380 ml of solution with pH = 8.94
erma4kov [3.2K]

Answer : The mass of sulfuric acid needed is 16.23\times 10^{-5}g.

Solution : Given,

pH = 8.94

Volume of solution = 380 ml = 380\times 10^{-3}      (1ml=10^{-3}L)

Molar mass of sulfuric acid = 98.079 g/mole

As we know,

pH+pOH=14\\pOH=14-8.94=5.06

pOH=-log[OH^-]

5.06=-log[OH^-]

[OH^-]=0.00000871=8.71\times 10^{-6}mole/L

Now we have to calculate the moles of OH^-.

Formula used : Moles=Concentration\times Volume

\text{ Moles of }[OH^-]=\text{ Concentration of }[OH^-]\times Volume\\\text{ Moles of }[OH^-]=(8.71\times 10^{-6}mole/L)\times (380\times 10^{-3}L)=3309.8\times 10^{-9}moles

For neutralization, equal number of moles of H^+ ions will neutralize same number of OH^- ions.

\text{ Moles of }[OH^-]=\text{ Moles of }[H^+]=3309.8\times 10^{-9}moles

As, H_2SO_4\rightarrow 2H^++SO^{2-}_4

From this reaction, we conclude that

2 moles of H^+ ion is given by the 1 mole of H_2SO_4

3309.8\times 10^{-9} moles of H^+ ion is given by \frac{3309.8\times 10^{-9}}{2}=1654.9\times 10^{-9} moles of H_2SO_4

Now we have to calculate the mass of sulfuric acid.

Mass of sulfuric acid = Moles of H_2SO_4 × Molar mass of sulfuric acid

Mass of sulfuric acid = (1654.9\times 10^{-9}moles)\times (98.079g/mole)=162310.94\times 10^{-9}=16.23\times 10^{-5}g

Therefore, the mass of sulfuric acid needed is 16.23\times 10^{-5}g.

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3 years ago
Why does a rubbed ballon stick to a wall
swat32
Static electricity is the answer
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4 years ago
What is the pH of a solution with [H+] of 1x10^-8 M?*<br> 15<br> -8<br> 8<br> 80
Serga [27]

Answer:

<h2>8</h2>

Explanation:

The pH of a solution can be found by using the formula

pH = - log [ {H}^{+} ]

From the question we have

ph  =  -  log(1 \times  {10}^{ - 8}  )  \\  = 8

We have the final answer as

<h3>8 </h3>

Hope this helps you

3 0
3 years ago
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