polyethylene contains HC=CH units.
mass of this is 26 gram/mol
number of such units =13500/26
Lead(II) nitrate will react with iron(III) chloride to produce the precipitate lead(II) chloride as shown in the balanced reaction
2FeCl3(aq) + 3Pb(NO3)2(aq) → 2Fe(NO3)3(aq) + 3PbCl2(s)
Calculating the amount of the precipitate lead(II) chloride each reactant will produce:
mol PbCl2 = 0.050L Pb(NO3)2 (0.100mol/1L)(3mol PbCl2/3mol Pb(NO3)2)
= 0.00500mol PbCl2
mol PbCl2 = 0.050L FeCl3 (0.100mol FeCl3/1L)(3mol PbCl2/2mol FeCl3) = 0.00750mol PbCl2
The reactant Pb(NO3)2 produces a lesser amount of the precipitate PbCl2, therefore, the lead(II) nitrate is the limiting reagent for this reaction.
Answer:
c. 3.00 M HCl
Explanation:
From dilution formula
C1V1 = C2V2
C1=?, V1= 10.0ml, C= 1.5, V2= 20.0ml
Substitute and Simplify
C1×10= 1.5×20
C1= 3.00M
The bond dipole moment<span> uses the idea of </span>electric dipole moment<span> to measure the </span>polarity<span> of a chemical bond within a </span>molecule<span>. It occurs whenever there is a separation of positive and negative charges. In the diagram above, option B exhibited a bond dipole moment. I hope this helps.</span>
<span>The answer is
101.1032 g/mol</span>
