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tatiyna
4 years ago
11

If hot dog buns come in packages of 6 and hot dog buns come in packages of 8 what is the least number of hot dog and buns you co

uld buy to have the same number of hot dogs and buns?
Mathematics
2 answers:
Kobotan [32]4 years ago
6 0
48 is the answer for sure
seropon [69]4 years ago
4 0
You would need to buy 48

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a firefighter dives at 7.5 m/sec from window to net. If window is 34 m above net, what speed does firefighter hit net. ACCELRATI
lianna [129]

Answer:

Step-by-step explanation:

This is more physics than math, but since "The book of nature is written in the language of mathematics"...

Anyway, the one-dimesional motion equation you want to use here resembles the quadratic we use to model parabolic motion. It is

v^2=v_0^2+2aΔx

where v is the final velocity of the firefighter, v₀ is the initial velocity of the firefighter, a is -9.8 m/s/s (negative because the motion is in the downward direction), and Δx is -34 m. This is also negative because where the firefighter lands is below the point at which he started. This is important, because if you leave the 34 as positive, you end up with a negative radicand...and that's not gonna work. Filling in the formula:

v^2=(7.5)^2+2(-9.8)(-34)

Paying close attention to significant digits here is important (at least it is when I teach physics in school!). Since there are 2 significant digits in 7.5, we need 2 in the product. 7.5 squared is 56.25 which will round to 56. Then on the right side of the plus sign, we need 2 significant digits as well since the number 2 is part of the equation. We don't count it as significant if it is part of the equation. 2(-9.8)(-34) = 666.4 but that will round to 670. NOW, since the rules for significant digits are different in multiplication and addition, you have to round each first, then take the square root of the sum, rounding at the end. In this case we will round to the place that holds the least significance between the 2 numbers. In our case that is the tens place, since the tens place is less significant than is the 1's place. The number 7 is in the tens place. (Following that rule is super tricky, and also quite maddening!)

What we have here is

v^2=56+670 and

v=\sqrt{56+670}

That leaves us with

v = 26.94438j

But don't forget we round that to the tens place which comes out in the end, finally, to

v = 30 m/s

 

5 0
3 years ago
Consider the line – 2x - 5y= 2.
Trava [24]

Answer:

Step-by-step explanation:

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2 years ago
Let f be the function given by f(x=sin(5x pi/4
sasho [114]
AP teachers for<span> course and exam preparation; permission </span>for<span> any other use ... 3. Question 2. Let f and g be the functions given by ( ). (. ) 2 1. </span>f x<span> x x. = − and. ( ) (. ) ..... </span>Let f be the function given by<span> ( ). ( ) </span>sin<span> 5. ,. </span>4<span>. </span>f x<span> x </span>π<span>. = + and let ( ). P x be the ...</span>
7 0
3 years ago
How do we write equations in slop intercept form and how do we do this entire page?
Alla [95]
So,...
the slope intercept form is y = mx+b
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so to start you off, 4x - 9y = 2

4x - 9y = 2
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6 0
3 years ago
A game shop sells marbles in clear plastic cylinders. Four marbles fit across the diameter of the cylinder and 10 marbles fit fr
slega [8]
To start, you know that this question is asking for the surface area of one of the cylinders, and the formula to finding the surface area of a cylinder is A=2πrh+2<span>πr^2.

Now, to find the surface area, you first need to figure out the height of the plastic cylinder and its radius. 
Since you know that the diameter (twice the radius) of the cylinder is equivalent to 4 marbles, and each marble has a diameter of 2 cm, the diameter of the cylinder would be 8 cm. Then, to find its radius, you divide by 2, so its radius is 4.
Now, since you know that the height of the cylinder is 10 marbles, you multiply 10 by 2 to get that the height is 20 cm tall. 
Since you now have the values of the height and the radius, plug the values into the surface area of a cylinder formula (r is radius and h is height).
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</span>
5 0
3 years ago
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