Let student tickets be s and adult tickets be a. The number of tickets sold of both adult and student then is s + a = 396. If each student ticket costs $3, then we represent the money equation by tacking the dollar amount onto the ticket. 3s is the cost of one student ticket. 4a is the cost of an adult ticket. The total money from the sales of both is 4a + 3s = 1385. We now have a system of equations we can solve for a and s. If s+a=396, then s = 396-a. We will sub that into the second equation to get 4a + 3(396-a) = 1385. Distributing we have 4a+1188-3a=1385. a = 197. That means there were 197 adult tickets sold. If s + a = 396, then s + 197 = 396 and s = 199. 197 adult tickets and 199 student tickets. There you go!
Answer:
<u>II. Second table</u>
A B Total
C 0.25 0.75 1.00
D 0.35 0.65 1.00
Total 0.30 0.70 1.00
Explanation:
<h2>Tables</h2>
<u>I. First table </u>
A B Total
C 0.25 0.25 0.50
D 0.25 0.25 0.50
Total 0.50 0.25 1.00
<u>II. Second table</u>
A B Total
C 0.25 0.75 1.00
D 0.35 0.65 1.00
Total 0.30 0.70 1.00
<u>III. Third table</u>
<u></u>
A B Total
C 0.75 0.25 0.50
D 0.25 0.75 0.50
Total 0.50 0.50 1.00
<u>IV. Fourth table</u>
A B Total
C 0.65 0.35 1.00
D 0.35 0.65 1.00
Total 1.00 1.00 1.00
<h2>Solution</h2>
A <em>conditional relative frequency table</em> shows the relative frequencies determined upon a row or column.
There are two types of relative conditional frequency table: 1) row conditional relative frequency, and 2) column conditional relative frequency.
When you divide the joint frequency by the marginal frequency of the column total you have the row conditional frequency table. When you dividethe joint frequency by the row total you have the colum conditional frequency table.
In a row conditional relative frequency each total of the right hand column equals 1. This is the case of the second table.
In a column conditional relative frequency each total of the bottom row equals 1. This is not happening with any of the shown tables.
Hence, only the second table could be a conditional relative frequency table.
Y=29-2(1)
y=29-2=27
(1,27)
y=29-2(3)
y=29-6=23
(3,23)
y=29-2(4)
y=29-8=21
(4,21)
y=29-2(5)
y=29-10=19
(5,19)
Answer:
142.932
Step-by-step explanation:
given that in triangle ABC, AC =24
Angle A = 30 and Angle B =45
If we draw altitude from C, we get
h = 24sin 30 = 12
Since BC = h (45, 45,90 triangle)
BC=12
By sine formula for triangle
Area of triangle
= 
-2
explanation:
coefficient is the number in front of the term it's asking for. so the number in front of x² would be the -2.
- another tip the b's represents x in that equation!!
