Answer:
Look below.
Step-by-step explanation:
For further reference I suggest looking at Khan academy videos of this.
A. log8 5/9
B. log9 4
C. log6 2^3
QUESTION:- EVALUATE THE EXPRESSION
EXPRESSION:-
![{( \sqrt[6]{27 {a}^{3} {b}^{4} } )}^{2}](https://tex.z-dn.net/?f=%7B%28%20%5Csqrt%5B6%5D%7B27%20%7Ba%7D%5E%7B3%7D%20%20%7Bb%7D%5E%7B4%7D%20%7D%20%29%7D%5E%7B2%7D%20)
<h3>ANSWER-></h3>
![\\ ANSWER->3ab \sqrt[3]{b} \: \: \: \: \: or \: \: 3a {b}^{ \frac{4}{3} }](https://tex.z-dn.net/?f=%20%5C%5C%20ANSWER-%3E3ab%20%5Csqrt%5B3%5D%7Bb%7D%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20or%20%5C%3A%20%5C%3A%203a%20%7Bb%7D%5E%7B%20%5Cfrac%7B4%7D%7B3%7D%20%7D%20)
Answer:
(2, 3 )
Step-by-step explanation:
Given the 2 equations
3x - 5y = - 9 → (1)
x + 2y = 8 → (2)
Multiplying (2) by - 3 and adding to (1) will eliminate the x- term, that is
- 3x - 6y = - 24 → (3)
Add (1) and (3) term by term to eliminate x
(3x - 3x) + (- 5y - 6y) = (- 9 - 24), that is
- 11y = - 33 ( divide both sides by - 11 )
y = 3
Substitute y = 3 into either of the 2 equations and solve for x
Substituting in (2)
x + 2(3) = 8
x + 6 = 8 ( subtract 6 from both sides )
x = 2
Solution is (2, 3 )
Answer:

Step-by-step explanation:
Here, we add up two polynomials shown.
The polynomials are:
![[-m^2 + 6]+[-4m^2 +7m + 2]](https://tex.z-dn.net/?f=%5B-m%5E2%20%2B%206%5D%2B%5B-4m%5E2%20%2B7m%20%2B%202%5D)
In order to add up the 2 polynomials shown, we have to see the "like terms" and add them up.
We add up the "
" terms and the constant (number) terms. There is one term with "m", so we leave it like that. Let's add up. Shown below:\
![[-m^2 + 6]+[-4m^2 +7m + 2]\\=-m^2-4m^2+6+2+7m\\=-5m^2+7m+8](https://tex.z-dn.net/?f=%5B-m%5E2%20%2B%206%5D%2B%5B-4m%5E2%20%2B7m%20%2B%202%5D%5C%5C%3D-m%5E2-4m%5E2%2B6%2B2%2B7m%5C%5C%3D-5m%5E2%2B7m%2B8)
This is the sum of the 2 polynomials shown: 
Answer:the base root becomes 45
Step-by-step explanation: