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AURORKA [14]
3 years ago
6

Determine the number of molecules present in 5.60 mol of nitrogen dioxide, the number of atoms of oxygen, and the number of nitr

ogen atoms.
Please explain how.
Chemistry
1 answer:
vaieri [72.5K]3 years ago
5 0
Nitrogen dioxide is NO2 (where the number 2 is a subscript that indicates the number of atoms in one molecule).

Use Avogadro's number: 1 mol of molecules = 6.022 * 10^ 23 molecules.

So, in 5.6 mol of NO2 there are 5,6 mol * 6.022 * 10^23 molecules / mol = 33.72 * 10^23 molecules = 3.372 * 10^24 molecules of NO2.

There are the same number of N atoms (because there is 1 atom of N in 1 molecule) and there are the double of O atoms (becasue there are 2 atoms of O in 1 molecule) => 3.372 * 10 ^24 atomsof N and 6.744 atoms of O.

Answer: 3.372 * 10^24 molecules of NO2, 3.372 * 10^24 atoms of N and 6.744 atoms of O.
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sukhopar [10]

Using the equation, pH = − log [H+] , we can solve for [H+] as,

− pH = log [H+] ,

[H+] = 10−pH.

Exponentiate both sides with base 10 to "undo" the common logarithm. The hydrogen ion concentration of blood with pH 7.4 is,

[H+] = 10−7.4 ≈ 0.0000040 = 4.0 × 10−8 M.

5 0
3 years ago
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What is the pH of this solution?
Vesnalui [34]

Answer:

pH = 11.216.

Explanation:

Hello there!

In this case, according to the ionization of ammonia in aqueous solution:

NH_3+H_2O\rightleftharpoons NH_4^++OH^-

We can set up its equilibrium expression in terms of x as the reaction extent equal to the concentration of each product at equilibrium:

Kb=\frac{[NH_4^+][OH^-]}{[NH_3]} \\\\1.80x10^{-5}=\frac{x*x}{0.150-x}

However, since Kb<<<1 we can neglect the x on bottom and easily compute it via:

1.80x10^{-5}=\frac{x*x}{0.150}\\\\x=\sqrt{1.80x10^{-5}*0.150}=1.643x10^{-3}M

Which is also:

[OH^-]=1.643x10^{-3}M

Thereafter we can compute the pOH first:

pOH=-log(1.643x10^{-3}M)\\\\pOH=2.784

Finally, the pH turns out:

pH=14-2.784\\\\pH=11.216

Regards!

5 0
3 years ago
Why would 18 be wrong for the atomic mass of an atom with 6 neutrons, 6 electrons, 6 protons?
11Alexandr11 [23.1K]
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Write the balanced molecular chemical equation for the reaction
Ierofanga [76]

The balanced molecular chemical equation for the reaction will be expressed as Cs₂CO₃ + Mg(NO₃)₂ -> 2CsNO₃ + MgCO₃

  • For any chemical equation to be balanced, the number of moles of elements in the reactants must be equal to that of the product.

  • According to the question, we are to write a balanced equation for the reaction  in aqueous solution for cesium carbonate and magnesium  nitrate
  • The chemical formula for Cesium carbonate is Cs₂CO₃
  • The chemical formula for magnesium  nitrate is Mg(NO₃)₂

Hence the balanced molecular chemical equation for the reaction will be expressed as Cs₂CO₃ + Mg(NO₃)₂ -> 2CsNO₃ + MgCO₃

Learn more here: brainly.com/question/11904811

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3 years ago
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