How does a parallel circuit differ from a series circuit

Physics

2 answers:

Lapatulllka [165]4 years ago

8 0

<span>A series circuit has one path for electrons, but a parallel circuit has more than one path.</span>

Mnenie [13.5K]4 years ago

8 0

A series circuit has only one path for current, while a parallel circuit has more than one

You might be interested in

In a physics motion study, students established a frame of reference for measurements. Which of the following is their most like

Irina-Kira [14]

I think it might be (D)

3 0

3 years ago

A uniform electric field of magnitude 375 n/c pointing in the positive x - direction acts on an electron, which is initially at

Finger [1]

(a) The force exerted by the electric field on the electron is given by the product between the electron charge q and the intensity of the electric field E:
$F=qE=(1.6 \cdot 10^{-19}C)(375 N/C)=6\cdot 10^{-17}N$
Under the action of this force, the electron moves by:
$\Delta x = 3.20 cm=0.032 m$
And the work done by the electric field on the electron is equal to the product between the magnitude of the force and the displacement of the electron. The sign has to be taken as positive, because the direction of the force is the same as the displacement of the electron, so:
$W=F \Delta x= (6\cdot 10^{-17}N)(0.032 m)=1.9 \cdot 10^{-18}J$

(b) The electron is initially at rest and it starts to move under the action of the electric field. This means that as it moves, it acquires kinetic energy and it loses potential energy. The change in potential energy is the opposite of the work done by the electric field:
$\Delta U = U_f - U_i = -1.9 \cdot 10^{-18} J$
Where Uf and Ui are the final and initial potential energy of the electron.

(c) For the conservation of energy, the sum of the kinetic energy and potential energy of the electron at the beginning of the motion and at the end must be equal:
$U_i + K_i = U_f + K_f$ (1)
where Ki and Kf are the initial and final kinetic energies.
The electron is initially at rest, so Ki =0, and we can rewrite (1) as
$U_i - U_f = - \Delta U = K_f = \frac{1}{2}m_e v_f^2$
and by using the mass of the electron me, we can find the value of the final velocity of the electron:
$v_f= \sqrt{ -\frac{2 \Delta U}{m_e} }= \sqrt{- \frac{2(-1.9 \cdot 10^{-18} J)}{9.1 \cdot 10^{-31} kg} } =2.04 \cdot 10^6 m/s$

7 0

3 years ago

Under very dim levels of illumination foveas react to increase the sensitivity of the optic nerve. rods are more light-sensitive

Alex777 [14]

Answer:

rods are more light sensitive than cones.

Explanation:

There are two types of photo receptors in retina of our eyes. 1 Rods and 2 Cones. Rods are about 120 million and they are more sensitive then the cones. But the rods are not sensitive to color. Cones help us in seeing the color and there are about 6 to 7 million cones that provide color sensitivity to our eyes. That is why in the dark or where their are dim levels of illumination rods provide us scotopic vision. Because rods are more light sensitive then the cones.

7 0

4 years ago

Read 2 more answers

A machine shop worker reports the mass of an aluminum cube as 176 g. If one side of the cube measures 4 cm, what is the density

Zarrin [17]

-- Since it's a cube, its length, width, and height are all the same 4 cm .

-- Its volume is (length x width x height) = 64 cm³ .

-- Density = (mass) / (volume)

= (176 g) / (64 cm³)

= 2.75 gm/cm³ .

6 0

3 years ago

Let's apply Snell's law to the refraction of light across a water–air interface. Suppose you kneel beside the fishpond in your b

Nataliya [291]

Answer:

The angle of refraction is 41.68°.

Explanation:

The refractive index for water is $n_2 = 1.333$ , and for air $n_1 = 1.00$ : the angle of light with the normal is $90^o-60^o = 30^o$ ; therefore Snell's law gives