Pls answer this

1.A steel cable is attached to a ring on the top of a street light. The weight of the street light is W . The other end of the c

mixer [17]

Answer:

a) Please find attached, the vector diagram regarding the question

i) The direction of the sum of the vectors is the negative direction of the vertical or y-axis

ii) The scale is 1 mm = 1 N

W = 25 N

The mass of W is approximately 2.55 kg

Explanation:

The given parameters are;

The angle of inclination of the cable to the vertical = 55°

The tension in the cable = 43.6 N

a) i) The direction of the vector sum of the two forces is given as the resultant of the two forces;

The component of the tension in the chain is given as follows;

Tension in the horizontal chain = x $\mathbf{ \hat i}$

The resolved force in the cable is given as follows;

Given that the force is acting upwards along the cable

F = 43.6 × -sin(55°) $\mathbf{ \hat i}$ + 43.6 × cos(55°) $\mathbf{ \hat j}$

F ≈ -35.72 $\mathbf{ \hat i}$ + 25 $\mathbf{ \hat j}$

Therefore, from ∑Fₓ = 0 and ∑F $_y$ = 0, since the horizontal force in the chain will balance the horizontal component of the tension in the cable, there will be no net horizontal force and the resultant force will have a direction of the vertical y-axis

ii)

Given that ∑F = 0, we have;

The tension in the cable is an horizontal force, therefore, we have;

∑Fₓ = 0

The tension in the horizontal chain + The horizontal component of the cable = 0

The tension in the horizontal chain - 35.72 N = 0

∴ The tension in the horizontal chain = 35.72 N

The weight of the street light + The vertical component of the tension = 0

The weight of the street light + 25 N = 0

Therefore;

The weight of the street light W = -25 N

The scale of the vector diagram used is <u>1 mm = 1 N</u>

W = -25 N

The mass of the street light = Weight of the street light/(Acceleration due to gravity)

The mass of the street light = 25 N/(9.81 m/s²) ≈ 2.55 kg

7 0

3 years ago

An iv curve is generated for two ohmic devices, one is a good conductor and the other is a good insulator. which one will have a

allochka39001 [22]

As per the question there are two ohmic devices.

The first ohmic device is a good conductor and the second one is a good insulator.

As per Ohm's law the current flowing through a conductor is directly proportional to the potential difference maintained across the two ends of a conductor at constant temperature and pressure. If V is the potential and I is the current flow through these Ohmic devices,then mathematically it can be written as-

V∝ I [ at constant temperature and pressure]

⇒V= IR

Here R is the proportionality constant called resistance of the material.

Hence the resistance R is calculated as -

$R=\frac{V}{I}$

Now a graph is plotted taking potential V on X-axis and current I along Y- axis.

The graph will be a straight line for conductor and will be a curve depending on the type of insulator.

The slope of this graph will give the resistance of the material.

An insulator is a substance through which current flow is very low as its resistance is very high.Hence the slope of the V-I curve is very large.

A conductor is that substance through which current is flown easily as the resistance of conductor is very low.Hence the slope of V-I curve is smaller,

5 0

3 years ago

Two people are talking at a distance of 3.0 m from where you are and you measure the sound intensity as 1.1 × 10-7 W/m2. Another

ioda

Answer:

$6.1875\times 10^{-8}$

Explanation:

Assuming uniform spread of sound with no significant reflections or absorption. We know that sound intensity varies $I=\frac {k}{r^{2}}$ where r is the distance

Since intensity is given then when at 3 m

$1.1\times 10^{-7}= \frac {k}{3^{2}}$

$k=3^{2}\times 1.1\times 10^{-7}= 9.9\times 10^{-7}$

Since we have the constant then at 4m

Intensity, $I= \frac {9.9\times 10^{-7}}{4^{2}}=6.1875\times 10^{-8}$

8 0

3 years ago

a pole vaulter at the top of his vault is 6.15 m in the air . if he has a gravitational potential energy of 4o42 j , what is his

Ksenya-84 [330]

<span>82.0 kg I am going to assume that there is a typo for the number of joules of energy. Doing a google search for this exact question showed this question multiple times with a value of 4942 joules which makes sense given how close the "o" key is to the "9" key. Because of this, I will assume that the correct value for the number of joules is 4942. With that in mind, here's the solution. The gravitational potential energy is expressed as the mass multiplied by the height, multiplied by the local gravitational acceleration. So: E = MHA Solving for M, the substituting the known values and calculating gives: E = MHA E/(HA) = M 4942/(6.15*9.8) = M 4942/60.27 = M 81.99767712 = M Rounding to 3 significant figures gives 82.0 kg</span>

4 0

4 years ago

Read 2 more answers

A sled with a mass of 32 kg is being pulled across the snow. If the friction force between the sled and the ground is 12 N, what

Sergeeva-Olga [200]

Answer:

Fa= 47.2N

Explanation:

3 0

3 years ago