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Lemur [1.5K]
4 years ago
7

Estimate the acceleration you subject yourself to if you walk into a brick wall at normal walking speed. (Make a reasonable esti

mate of your speed and of the time it takes you to come to a stop.) Give your reasoning, and make sure your estimate has units
Physics
1 answer:
xenn [34]4 years ago
4 0

Answer:

From certain assumptions that the walking speed is 2 m/s, and the stop time is 0.1 s the acceleration would be -20 m/s

Explanation:

Using the average acceleration formula:

a=\frac{\Delta v}{\Delta t} where \Delta v and \Delta t are the changes in the speed and time respectively.

We have by assuming that the walking speed is 2 m/s and the stop time is 0.1s which is equal to the change in time during the stopping.

\Delta v=v_f-v_i=0-2 m/s=-2 m/s, where v_i,v_f are the initial speed and final speed respectively, and \Delta t=0.1 s

Plugging the previous in the average acceleration formula we get

a=\frac{-2}{0.1}=-20\, m/s where the minus sign indicates an acceleration in the opposite direction of the motion (or in other word opposite to the speed's direction).

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Passengers on a carnival ride move at constant speed in a horizontal circle of radius 5.0 m, making a complete circle in 4.0 s.
Nataliya [291]

Answer:

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7 0
3 years ago
Gordon throws a baseball into the air. It rises, stops when it reaches its greatest height, and then falls back to the ground. A
dangina [55]
Both C and D are technically correct. But I’d go with D in this instance.
5 0
3 years ago
At what value of angle between two vectors will the resultant of the two vectors be maximum?
yan [13]

The resultant is maximum when the angle between the two vectors is zero

Explanation:

The formula to calculate the resultant of two vectors A, B is the following:

R=\sqrt{A^2+B^2+2ABcos \theta}

where

A is the magnitude of vector A

B is the magnitude of vector B

\theta is the angle between the directions of A and B

This formula can be derived by applying the parallelogram law.

From the formula, we observe that:

- When \theta=0^{\circ} (vectors A and B parallel), cos \theta = 1. so the resultant becomes simply

R=\sqrt{A^2+B^2 + 2AB}=\sqrt{(A+B)^2}=A+B

- When \theta = 90^{\circ} (vectors A and B perpendicular), cos \theta = 0, so the resultant becomes

R=\sqrt{A^2+B^2}

- When \theta=180^{\circ} (vectors A and B anti-parallel), cos \theta = -1, so the resultant becomes

R=\sqrt{A^2+B^2 - 2AB}=\sqrt{(A-B)^2}=|A-B|

By looking at the three cases and at the formula, we see that the maximum value of the resultant is when the angle between the two vectors is zero, since in that case the resultant is simply obtained by adding the magnitudes of the two vectors.

Learn more about vector addition:

brainly.com/question/4945130

brainly.com/question/5892298

#LearnwithBrainly

3 0
3 years ago
1.A particle is moving up an inclined plane. Its velocity changes from 15m/s to 10m/s in two seconds. What is its acceleration?
FrozenT [24]

\huge{ \underline{ \boxed{ \bf{ \blue{Solution:}}}}}

<h3><u>Provided</u><u>:</u><u>-</u></h3>
  • Initial velocity = 15 m/s
  • Final velocity = 10 m/s
  • Time taken = 2 s

<h3><u>To FinD:-</u></h3>
  • Accleration of the particle....?

<h3><u>How</u><u> </u><u>to</u><u> </u><u>solve</u><u>?</u></h3>

We will solve the above Question by using equations of motion that are:-

  • v = u + at
  • s = ut + 1/2 at²
  • v² = u² + 2as

Here,

  • v = Final velocity
  • u = Initial velocity
  • a = acceleration
  • t = time taken
  • s = distance travelled

<h3><u>Work</u><u> </u><u>out</u><u>:</u></h3>

By using first equation of motion,

⇛ v = u + at

⇛ 10 = 15 + a(2)

⇛ -5 = 2a

Flipping it,

⇛ 2a = -5

⇛ a = -2.5 m/s² [ANSWER]

❍ Acclearation is negative because final velocity is less than Initial velocity.

<u>━━━━━━━━━━━━━━━━━━━━</u>

5 0
4 years ago
18. A net force of 1.0N acts on a 4.0-kg object, initially at rest, for 4.0 seconds. What is the distance the object moves durin
hjlf
Acceleration = force/mass
1/4
s=ut+1/2at^2
0*4+1/2*1/4*4^2
1/2*1/4*16
1/2*4
=2
6 0
4 years ago
Read 2 more answers
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