You must first normalize this in order to use a Z-score table. To convert what you have into a Z score you must use this formula: (x- mean) /standard deviation. In your case (334-310)/12=2. So now you want the probability that a score is greater than 334, which in turn means you want P(Z>2)=1-P(Z<2)=1-.9772=0.0228=2.28%.
Cross the y-axis in x=0
therfore:
if x=0; y=3*0+2=2; ⇒ P(0,2)
solution: P(0,2).
70 or +70
To represent a positive integer
Chegg porter averages 21 points per basketball
game with a standard deviation of 4.5 points.
suppose porter's points per basketball game
are normally distributed. let x
