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juin [17]
2 years ago
10

Newton’s Third Law of Motion states that for every action there is an equal and opposite reaction. Which of these illustrates Ne

wton’s Third Law?
A: Two students of similar mass run into each other. They bounce off each other when they collide.

B: Two students of similar mass run side by side into a wall and punch holes of equal size before emerging on the other side.

C: Two students of similar mass run in opposite directions, but one accelerates at twice the rate of the other.

D: Two students of similar mass run at the same speed in opposite directions on a track. They will collide with 400 Newtons of force in 400 meters.
Physics
1 answer:
Angelina_Jolie [31]2 years ago
4 0

Answer:

A

Explanation:

An equal and opposite reaction happens when they run into eachother and bounce off. What makes it equal is when they have the same amount of force applied when they collided.

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Gravity pulls to the centre of the earth. A ship floats in water because the water pushing it up (upthrust) is equal to the force<span> of gravity (weight) pulling it </span>down<span>. Friction also occurs when objects move through air. This is </span>called<span>air resistance.</span>
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According to Oxford Dictionaries, a spit take is an act of suddenly spitting out liquid one is drinking in response to something
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Answer:

The pressure is p_1 = 4051.4 \ Pa

Explanation:

From the question we are told that

     The gauge pressure at the mouth is  p_1

     The radius of the column is  r_2 =  4 \ mm  =  0.004 \ m

    The speed of the liquid outside the body is  v_2 =  3.1 \ m/s

      The area of the column is  A_2

       The area inside the mouth A_1 = 10 A_2

Generally according to continuity equation

       v_1 A_1 =  v_2 A_2

=>       v_ 1 = v_2 *  \frac{A_2}{A_1}

=>      v_ 1 = 3.1 *  \frac{1}{10}

=>        v_ 1 = 0.31 \ m/s

So

      A_1 = 10A_2

=>   \pi * r_1^2 = 10(\pi * r_2^2)

=>   r_1 = 10 * r_2

substituting values

        r_1 = 10 * 0.004

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Now the height of inside the mouth is  h_1 =  d =  2r_1 =  2* 0.04 =  0.08\ m

Now the height of the column is  h_2 =  d =  2r_2 =  2* 0.004 =  0.008\ m

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        p_1 =  [\frac{1}{2}  \rho v_2^2 + h_2 \rho g +p_2] -[\frac{1}{2} \rho * v_1^2 + h_1 \rho g ]

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        p_2 is the gauge pressure of the atmosphere which is  zero

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       p_1 =  [(0.5 * 1000 * (3.1)^2) +(0.008 * 1000 * 9.8) + 0]-

                                                  [(0.5 * 1000 * 0.31^2) + (0.08*1000 * 9.8)]                          

       p_1 = 4051.4 \ Pa

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Therefore

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'

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