Well it's energy comes from the sun since the sun gives it sunlight to help it grow
G = 9.81 m/sec^2) g = 9.81
![\frac{meters}{ second^{2} }](https://tex.z-dn.net/?f=%20%5Cfrac%7Bmeters%7D%7B%20second%5E%7B2%7D%20%7D%20)
<span>Solving for velocity : </span>
![velocity^{2}](https://tex.z-dn.net/?f=%20velocity%5E%7B2%7D%20)
<span> = 2gh </span>
<span>v = </span>
![2gh^{ \frac{1}{2} }](https://tex.z-dn.net/?f=%202gh%5E%7B%20%5Cfrac%7B1%7D%7B2%7D%20%7D%20)
<span>v = (2 x 9.81 x 10)^1/2 </span>
<span>v = 196.2 m/sec (answer)</span>
Answer:
write the name of any five districts of nepal
A rocket ship is accelerated by the SRB and the main engines for 2.0 minutes and the main engines for 8.5 minutes after the launch. The acceleration of the ship during the first 2.0 minutes is 11 m/s² (D).
A rocket ship has several engines and thrusters. We can divide its initial movement into 2 parts:
- From t = 0 min to t = 2.0 min, the SRB and the main engines act together and the speed goes from 0 m/s (rest) to 1341 m/s.
- From t = 2.0 min to t = 8.5 min, the main engines alone accelerate the ship form 1341 m/s to 7600 m/s.
We want to know the acceleration in the first part (first 2.0 minutes). We need to consider that:
- The speed increases from 0 m/s to 1341 m/s.
- The time elpased is 2.0 min.
- 1 min = 60 s.
The acceleration of the ship during the first 2.0 minutes is:
![a = \frac{\Delta v }{t} ) \frac{(1341m/s-0m/s)}{2.0min} \times \frac{1min}{60s} = 11 m/s^{2}](https://tex.z-dn.net/?f=a%20%3D%20%5Cfrac%7B%5CDelta%20v%20%7D%7Bt%7D%20%29%20%5Cfrac%7B%281341m%2Fs-0m%2Fs%29%7D%7B2.0min%7D%20%5Ctimes%20%5Cfrac%7B1min%7D%7B60s%7D%20%20%3D%2011%20m%2Fs%5E%7B2%7D)
A rocket ship is accelerated by the SRB and the main engines for 2.0 minutes and the main engines for 8.5 minutes after the launch. The acceleration of the ship during the first 2.0 minutes is 11 m/s² (D).
Learn more: brainly.com/question/16274121