Answer:
B=9.1397*10^-4 Tesla
Explanation:
To find the velocity first we put kinetic energy og electron is equal to potential energy of electron
K.E=P.E
![\frac{1}{2}*m*v^{2} =e*V](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%2Am%2Av%5E%7B2%7D%20%20%3De%2AV)
where :
m is the mass of electron
v is the velocity
V is the potential difference
eq 1
Radius of electron moving in magnetic field is given by:
eq 2
where:
m is the mass of electron
v is the velocity
q=e=charge of electron
B is the magnitude of magnetic field
Put v from eq 1 into eq 2
![R=\frac{m*\sqrt{\frac{2*e*V}{m} } }{e B}](https://tex.z-dn.net/?f=R%3D%5Cfrac%7Bm%2A%5Csqrt%7B%5Cfrac%7B2%2Ae%2AV%7D%7Bm%7D%20%7D%20%7D%7Be%20B%7D)
![B=\sqrt{\frac{2*m*V}{e*R^{2} } }](https://tex.z-dn.net/?f=B%3D%5Csqrt%7B%5Cfrac%7B2%2Am%2AV%7D%7Be%2AR%5E%7B2%7D%20%7D%20%7D)
![B=\sqrt{\frac{2*(9.31*10^{-31})*(2.12*10^{3}) }{(1.60*10^{-19})*(0.170)^{2} } }](https://tex.z-dn.net/?f=B%3D%5Csqrt%7B%5Cfrac%7B2%2A%289.31%2A10%5E%7B-31%7D%29%2A%282.12%2A10%5E%7B3%7D%29%20%20%7D%7B%281.60%2A10%5E%7B-19%7D%29%2A%280.170%29%5E%7B2%7D%20%20%7D%20%7D)
B=9.1397*10^-4 Tesla
Thank you for your question, what you say is true, the gravitational force exerted by the Earth on the Moon has to be equal to the centripetal force.
An interesting application of this principle is that it allows you to determine a relation between the period of an orbit and its size. Let us assume for simplicity the Moon's orbit as circular (it is not, but this is a good approximation for our purposes).
The gravitational acceleration that the Moon experience due to the gravitational attraction from the Earth is given by:
ag=G(MEarth+MMoon)/r2
Where G is the gravitational constant, M stands for mass, and r is the radius of the orbit. The centripetal acceleration is given by:
acentr=(4 pi2 r)/T2
Where T is the period. Since the two accelerations have to be equal, we obtain:
(4 pi2 r) /T2=G(MEarth+MMoon)/r2
Which implies:
r3/T2=G(MEarth+MMoon)/4 pi2=const.
This is the so-called third Kepler law, that states that the cube of the radius of the orbit is proportional to the square of the period.
This has interesting applications. In the Solar System, for example, if you know the period and the radius of one planet orbit, by knowing another planet's period you can determine its orbit radius. I hope that this answers your question.
Answer:
C. Supervising the game to make sure teams are playing fairly
weightlessness is the complete or near complete absense of the sensation of weight.
when in freefall,the only force acting upon your body is the force of gravity a noun contact force.since the gravity cannot be felt without any other opposing forces,you would have no sensation of it.you would feel weightless when in a state of freefall.