Radioactive always means first order reaction
the half life of a first order reaction is t(1/2)=ln(2)/k. addtional info is needed to complete the calculations but this will determine the rate constant k. then for a first order reaction: <span>ln[A] = ln[Ao] - kt where [A] is the final amount left after time t (3 weeks) and [Ao] is the inital amount. </span>
Answer:
The answer to your question is below
Explanation:
I just write the formulas of the reactants and products and balanced the reactions.
a)
3H₂(g) + N₂(g) ⇒ 2NH₃
b)
2K + 2H₂O ⇒ 2KOH + H₂ (g)
c)
2Al(s) + Fe₂O₃ ⇒ Al₂O₃ + 2Fe
d)
Fe₂O₃ + 2Al ⇒ Al₂O₃ + 2Fe
e)
Ba(OH)₂ + 2HBr ⇒ BaBr₂ + 2H₂O
f)
CaCO₃ + Δ ⇒ CaO + CO₂
Answer:
lAs can be seen from the chemical equation, each mole of
F
e
2
C
O
3
needs 3 moles of
C
O
. If 30 moles of
C
O
are used, only 10 moles of
F
e
2
C
O
3
can be reduced, generating 20 moles of
F
e
, corresponding to 1117 grams of iron.
Answer:
Dude this one is confusing because you are not giving the price of the object.
Explanation: